使用重载运算符来实现另一个运算符重载可以吗? [英] Is it okay to use an overloaded operator to implement another operator overload?

问题描述

例如，如果我重载了+运算符

For instance if I have overloaded a + operator

myClass & operator + (const myClass & rhs)

，也重载=运算符

myClass & operator = (const myClass & rhs)

两个操作员都工作正常.我可以在+ =运算符重载中使用此重载运算符吗?

both operators are working fine. Can I use this overloaded operator in my += operator overload?

myClass & operator += (const myClass & rhs){

*this = *this + progA;

return *this;

}

上面的代码可以正常工作.我只想知道这是否是好的代码编写实践，还是应该为+ =运算符重用而重复使用前两个实现中的代码.

The above code is working okay. I just want to know if this is good code writing practice or I should re-use the code from the two previous implementations for the += operator overload.

推荐答案

您可以这样做.但是，更常见的是使用operator+=而不是其他方法来实现operator+.

You can do that. However, it is more common to implement operator+ using operator+= instead of the other way around.

myClass & operator += (const myClass & rhs) { ... )

// Return by value.
// const member function.
myClass operator + (const myClass & rhs) const
{
    myClass ret = *this; // Uses copy constructor, not assignment.
    return ret += rhs;
}

界面

myClass & operator + (const myClass & rhs);

不是惯用语，因为您不能做到

is not idiomatic since you cannot do the equivalent of

int a = 10 + 20;

使用

MyClass a = MyClass(args...) + MyClass(args...);

由于RHS中的第一个对象是临时对象，因此无法正常工作.

won't work since the first object in RHS is a temporary object.

这篇关于使用重载运算符来实现另一个运算符重载可以吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！