将 pandas 列转换为DateTime II [英] Convert Pandas Column to DateTime II
问题描述
我正在尝试将一列DateTime字符串转换为熊猫可理解的Datetime格式.当然，我已经用谷歌搜索并尝试了几种解决方案. 将熊猫"列转换为DateTime
I am trying to convert a column of DateTime Strings into a Pandas-comprehensible Datetime Format. Of course I already googled and tried several solutions. Convert Pandas Column to DateTime
对于我来说，这似乎是最令人鼓舞的，但是两种推荐的方法都不适用于我的数据集. 细节: 数据集名称:co，
This one appeared the most encouraging for me but both recommended ways did not work for my dataset. The details: Dataset name: co,
列:索引列，
格式:2015年7月15日24:00，前后没有空白.
Format: 15.07.2015 24:00 with no more blancs before or after.
我的努力:
co['newdate'] = pd.to_datetime(co.index, format='%d.%m.%Y %H:%M')
在将Index-col转换为名为"Datum"的"normal"列后，我尝试了下一个
The next one I tried after I transformed the Index-col to a "normal" column named "Datum"
co['newdate'] = co['Datum'].apply(lambda x: dt.datetime.strptime(x,'%d.%m.%Y %H:%M'))
错误:时间数据'15 .07.2015 24:00'与格式'％d.％m.％Y％H:％M'不匹配
The error: time data '15.07.2015 24:00' does not match format '%d.%m.%Y %H:%M'
在两个解决方案中均发生此错误.有人有主意吗?
this error occurs in both solutions. Anyone an idea?
推荐答案
您的格式字符串正确，但您的数据不正确，24不是有效的小时部分，因此出现错误:
Your format string is correct but your data is not, 24 is not a valid hour component hence the error:
In [138]:
pd.to_datetime('15.07.2015 24:00', format = '%d.%m.%Y %H:%M')
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
C:\WinPython-64bit-3.4.3.5\python-3.4.3.amd64\lib\site-packages\pandas\tseries\tools.py in _convert_listlike(arg, box, format)
329 try:
--> 330 values, tz = tslib.datetime_to_datetime64(arg)
331 return DatetimeIndex._simple_new(values, None, tz=tz)
pandas\tslib.pyx in pandas.tslib.datetime_to_datetime64 (pandas\tslib.c:23823)()
TypeError: Unrecognized value type: <class 'str'>
During handling of the above exception, another exception occurred:
ValueError Traceback (most recent call last)
<ipython-input-138-1546fb6950f0> in <module>()
----> 1 pd.to_datetime('15.07.2015 24:00', format = '%d.%m.%Y %H:%M')
C:\WinPython-64bit-3.4.3.5\python-3.4.3.amd64\lib\site-packages\pandas\tseries\tools.py in to_datetime(arg, errors, dayfirst, utc, box, format, exact, coerce, unit, infer_datetime_format)
343 return _convert_listlike(arg, box, format)
344
--> 345 return _convert_listlike(np.array([ arg ]), box, format)[0]
346
347 class DateParseError(ValueError):
C:\WinPython-64bit-3.4.3.5\python-3.4.3.amd64\lib\site-packages\pandas\tseries\tools.py in _convert_listlike(arg, box, format)
331 return DatetimeIndex._simple_new(values, None, tz=tz)
332 except (ValueError, TypeError):
--> 333 raise e
334
335 if arg is None:
C:\WinPython-64bit-3.4.3.5\python-3.4.3.amd64\lib\site-packages\pandas\tseries\tools.py in _convert_listlike(arg, box, format)
305 try:
306 result = tslib.array_strptime(
--> 307 arg, format, exact=exact, coerce=coerce
308 )
309 except (tslib.OutOfBoundsDatetime):
pandas\tslib.pyx in pandas.tslib.array_strptime (pandas\tslib.c:39900)()
ValueError: time data '15.07.2015 24:00' does not match format '%d.%m.%Y %H:%M' (match)
23:59可以很好地解析
In [139]:
pd.to_datetime('15.07.2015 23:59', format = '%d.%m.%Y %H:%M')
Out[139]:
Timestamp('2015-07-15 23:59:00')
您需要将24替换为0以便对其进行解析:
You need to replace 24 with 0 in order for this to parse:
In [140]:
pd.to_datetime('15.07.2015 00:00', format = '%d.%m.%Y %H:%M')
Out[140]:
Timestamp('2015-07-15 00:00:00')
So what you can do is call the vectorised str.replace to fix these errant hour values:
In [144]:
df = pd.DataFrame({'date':['15.07.2015 24:00']})
print(df)
df['date'] = df['date'].str.replace('24:','00:')
print(df)
pd.to_datetime(df['date'], format = '%d.%m.%Y %H:%M')
date
0 15.07.2015 24:00
date
0 15.07.2015 00:00
Out[144]:
0 2015-07-15
Name: date, dtype: datetime64[ns]
因此，您可以这样做:
co.index = co.index.str.replace('24:','00:')
然后像以前一样转换
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