如何将YAML文件解析/读入Python对象? [英] How to parse/read a YAML file into a Python object?

问题描述

如何将YAML文件解析/读入Python对象?

How to parse/read a YAML file into a Python object?

例如，此YAML:

Person:
  name: XYZ

此Python类:

class Person(yaml.YAMLObject):
  yaml_tag = 'Person'

  def __init__(self, name):
    self.name = name

我正在使用PyYAML.

I am using PyYAML by the way.

推荐答案

如果您的YAML文件如下所示:

If your YAML file looks like this:

# tree format
treeroot:
    branch1:
        name: Node 1
        branch1-1:
            name: Node 1-1
    branch2:
        name: Node 2
        branch2-1:
            name: Node 2-1

您已经这样安装了PyYAML:

pip install PyYAML

Python代码如下:

And the Python code looks like this:

import yaml
with open('tree.yaml') as f:
    # use safe_load instead load
    dataMap = yaml.safe_load(f)

变量dataMap现在包含一个包含树数据的字典.如果使用PrettyPrint打印dataMap，您将得到类似的信息:

The variable dataMap now contains a dictionary with the tree data. If you print dataMap using PrettyPrint, you will get something like:

{'treeroot': {'branch1': {'branch1-1': {'name': 'Node 1-1'},
    'name': 'Node 1'},
    'branch2': {'branch2-1': {'name': 'Node 2-1'},
    'name': 'Node 2'}}}

因此，现在我们已经了解了如何将数据获取到我们的Python程序中.保存数据同样简单:

So, now we have seen how to get data into our Python program. Saving data is just as easy:

with open('newtree.yaml', "w") as f:
    yaml.dump(dataMap, f)

您有一个字典，现在您必须将其转换为Python对象:

You have a dictionary, and now you have to convert it to a Python object:

class Struct:
    def __init__(self, **entries): 
        self.__dict__.update(entries)

然后您可以使用:

>>> args = your YAML dictionary
>>> s = Struct(**args)
>>> s
<__main__.Struct instance at 0x01D6A738>
>>> s...

并遵循"将Python dict转换为对象".

有关更多信息，请参见 pyyaml.org 和

For more information you can look at pyyaml.org and this.

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