如何在URL中的最后一个斜杠之后获取所有内容? [英] How to get everything after last slash in a URL?

问题描述

如何提取Python中URL中最后一个斜杠之后的内容?例如，这些URL应该返回以下内容:

How can I extract whatever follows the last slash in a URL in Python? For example, these URLs should return the following:

URL: http://www.test.com/TEST1
returns: TEST1

URL: http://www.test.com/page/TEST2
returns: TEST2

URL: http://www.test.com/page/page/12345
returns: 12345

我尝试了urlparse，但这给了我完整的路径文件名，例如page/page/12345.

I've tried urlparse, but that gives me the full path filename, such as page/page/12345.

推荐答案

您不需要花哨的东西，只需参阅

You don't need fancy things, just see the string methods in the standard library and you can easily split your url between 'filename' part and the rest:

url.rsplit('/', 1)

因此，您可以简单地通过以下方式获得感兴趣的部分:

So you can get the part you're interested in simply with:

url.rsplit('/', 1)[-1]

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