在最后一个正斜杠或反斜杠之前的所有内容的正则表达式 [英] Regex for everything before last forward or backward slash

问题描述

我需要一个正则表达式来查找字符串中的所有内容，包括最后一个 \ 或/.

例如，c:\directory\file.txt 应该导致 c:\directory\

解决方案

试试这个:(Rubular)

/^(.*[\\\/])/

说明:

<前>^ 行/字符串的开始( 开始捕获组.* 贪婪地匹配任何字符[\\\/] 匹配反斜杠或正斜杠) 结束捕获组

由于.*的贪婪性，匹配的斜线将是最后一个.

如果您的语言支持(或需要)它，您可能希望对正则表达式使用与 / 不同的分隔符，这样您就不必转义正斜杠.

此外，如果您正在解析文件路径，您可能会发现您的语言已经有一个可以执行此操作的库.这比使用正则表达式要好.

I need a regex that will find everything in a string up to and including the last \ or /.

For example, c:\directory\file.txt should result in c:\directory\

解决方案

Try this: (Rubular)

/^(.*[\\\/])/

Explanation:

^      Start of line/string
(      Start capturing group
.*     Match any character greedily
[\\\/] Match a backslash or a forward slash
)      End the capturing group  

The matched slash will be the last one because of the greediness of the .*.

If your language supports (or requires) it, you may wish to use a different delimiter than / for the regular expression so that you don't have to escape the forward-slash.

Also, if you are parsing file paths you will probably find that your language already has a library that does this. This would be better than using a regular expression.

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