Python:如何在字符串拆分中包含定界符? [英] Python: How can I include the delimiter(s) in a string split?

问题描述

我想用多个定界符分割一个字符串，但是将定界符保留在结果列表中.我认为这是第一步，解析任何一种公式都是很有用的，我怀疑有一个不错的Python解决方案.

I would like to split a string, with multiple delimiters, but keep the delimiters in the resulting list. I think this is a useful thing to do an an initial step of parsing any kind of formula, and I suspect there is a nice Python solution.

有人在Java中问了类似的问题

Someone asked a similar question in Java here.

例如，典型的拆分如下所示:

For example, a typical split looks like this:

>>> s='(twoplusthree)plusfour'
>>> s.split(f, 'plus')
['(two', 'three)', 'four']

但是我正在寻找一种添加加号(或保留它)的好方法:

But I'm looking for a nice way to add the plus back in (or retain it):

['(two', 'plus', 'three)', 'plus', 'four']

最终，我想对每个运算符和括号进行此操作，因此，如果有一种获取方法

Ultimately I'd like to do this for each operator and bracket, so if there's a way to get

['(', 'two', 'plus', 'three', ')', 'plus', 'four']

一劳永逸，然后一切都会好起来.

all in one go, then all the better.

推荐答案

您可以使用Python的re模块来做到这一点.

You can do that with Python's re module.

import re
s='(twoplusthree)plusfour'
list(filter(None, re.split(r"(plus|[()])", s)))

如果只需要迭代器，则可以省略列表.

You can leave out the list if you only need an iterator.

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