使用SQL Server通过定界符在列中拆分字符串 [英] Split string in columns by delimiter using SQL Server

查看:154
本文介绍了使用SQL Server通过定界符在列中拆分字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要使用定界符在列中拆分我的一个列值,下面是表结构。

I need to split my one column value in column using delimiter, below is the table structure.

create table #a
(
    id int, 
    timeline varchar(100)
)

insert into #a
values (1, 'Semi Annual Q2 (May/June/July) & Q4 (Nov/Dec/Jan)'),
       (2, 'Semi Annual Q1 (Feb/Mar/Apr) & Q3 (Aug/Sep/Oct)'),
       (3, 'Annual Q3 (Aug/Sep/Oct)'),
       (4, 'Annual Q2 (May/June/July)'),
       (5, 'Annual Q4 (Nov/Dec/Jan)'),
       (6, 'Semi Annual Q1 (Jan/Feb/Mar) & Q3 (July/Aug/Sep)')

select * from #a

输出我想用'/'分隔符分割时间轴值,并为独立的月份和所有月份应按顺序排列,看起来像下面的示例。

Output I want to split timeline values by ' / ' delimiter and make separate column for separate month and all month should be in sequence, which look like a below sample.

ID  M1   M2    M3    M4    M5    M6
---------------------------------------
1   May  June  July  Nov   Dec   Jan
2   Feb  Mar   Apr   Aug   Sep   Oct
3   Aug  Sep   Oct   NULL  NULL  NULL
4   May  June  July  NULL  NULL  NULL
5   Nov  Dec   Jan   NULL  NULL  NULL
6   Jan  Feb   Mar   July  Aug   Sep

到目前为止,我已经尝试过:

So far, I have tried this:

select
    timeline,
    substring((substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline) - 1)), 1, charindex('/', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline) - 1)) - 1) as M1,
    replace(replace(right(substring(substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)), 1, charindex(')', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)))), charindex('/', reverse(substring(substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline)), 1, charindex(')', substring(timeline, CHARINDEX('(', timeline) + 1, len(timeline))))), 4)), '/', ''), ')', '') as M3
from 
    #a;

这不是代码,也很繁琐。如果您有有效的方法,请提供帮助。

which is not a code and too tedious also. please help if you have efficient way to do this.

推荐答案

在以下解决方案中使用的SplitCSVToTable8K函数与DelimitedSplit8K相同。上面提到的函数...

The SplitCSVToTable8K function being used in the following solution, is the same DelimitedSplit8K function mentioned above...

在解决方案中如何使用它:

Here's how to use it in the solution:

WITH 
    cte_ParseTimeline AS (
        SELECT 
            a.id,
            rn = ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY sc.ItemNumber),
            sc.Item
        FROM 
            #a a
            CROSS APPLY dbo.SplitCSVToTable8K(REPLACE(REPLACE(a.timeline, '(', '/'), ')', '/'), '/') sc
        WHERE 
            sc.Item LIKE ('[A-Z][a-z][a-z]')
            OR 
            sc.Item LIKE ('[A-Z][a-z][a-z][a-z]')
        )
SELECT 
    pt.id,
    M1 = MAX(CASE WHEN pt.rn = 1 THEN pt.Item END),
    M2 = MAX(CASE WHEN pt.rn = 2 THEN pt.Item END),
    M3 = MAX(CASE WHEN pt.rn = 3 THEN pt.Item END),
    M4 = MAX(CASE WHEN pt.rn = 4 THEN pt.Item END),
    M5 = MAX(CASE WHEN pt.rn = 5 THEN pt.Item END),
    M6 = MAX(CASE WHEN pt.rn = 6 THEN pt.Item END)
FROM 
    cte_ParseTimeline pt
GROUP BY
    pt.id;

结果...

id          M1    M2    M3    M4    M5    M6
----------- ----- ----- ----- ----- ----- -----
1           May   June  July  Nov   Dec   Jan
2           Feb   Mar   Apr   Aug   Sep   Oct
3           Aug   Sep   Oct   NULL  NULL  NULL
4           May   June  July  NULL  NULL  NULL
5           Nov   Dec   Jan   NULL  NULL  NULL
6           Jan   Feb   Mar   July  Aug   Sep

这篇关于使用SQL Server通过定界符在列中拆分字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆