python re.split超前模式 [英] python re.split lookahead pattern
问题描述
我正在尝试re.split从日志文件中获取带有标题和常规结构的BCF#，BTS#和LAC，CI:
I'm trying re.split to get BCF#, BTS# and LAC, CI from logfile with the header and regular structure inside:
==================================================================================
RADIO NETWORK CONFIGURATION IN BSC:
E P B
F T R C D-CHANNEL BUSY
AD OP R ET- BCCH/CBCH/ R E S O&M LINK HR FR
LAC CI HOP ST STATE FREQ T PCM ERACH X F U NAME ST
/GP
===================== == ====== ==== == ==== =========== = = == ===== == === ===
BCF-0010 FLEXI MULTI U WO 2 LM10 WO
10090 31335 BTS-0010 U WO 0 0
KHAKHAATT070D BB/-
7
TRX-001 U WO 779 0 1348 MBCCH+CBCH P 0
TRX-002 U WO 659 0 1348 1
TRX-003 U WO 661 0 1348 2
TRX-004 U WO 670 0 1348 0
TRX-005 U WO 674 0 1348 1
10090 31336 BTS-0011 U WO 0 0
KHAKHAATT200D BB/-
7
TRX-006 U WO 811 0 1348 MBCCH+CBCH P 2
TRX-009 U WO 845 0 1349 2
TRX-010 U WO 819 0 1349 0
TRX-011 U WO 823 0 1349 1
TRX-012 U WO 836 0 1349 2
10090 31337 BTS-0012 U WO 0 0
KHAKHAATT340D BB/-
5
TRX-013 U WO 799 0 1349 MBCCH+CBCH P 0
TRX-014 U WO 829 0 1349 1
TRX-017 U WO 831 0 1302 2
TRX-018 U WO 834 0 1302 1
TRX-019 U WO 853 0 1302 0
TRX-020 U WO 858 0 1302 2
TRX-021 U WO 861 0 1302 1
BCF-0020 FLEXI MULTI U WO 0 LM20 WO
10090 30341 BTS-0020 U WO 0 0
KHAKHABYT100G BB/-
1
TRX-001 U WO 14 0 1856 MBCCH+CBCH P 0
TRX-002 U WO 85 0 1856 1
10090 30342 BTS-0021 U WO 0 0
KHAKHABYT230G BB/-
1
TRX-003 U WO 4 0 1856 MBCCH+CBCH P 2
TRX-004 U WO 12 0 1856 0
10090 30343 BTS-0022 U WO 0 0
KHAKHABYT340G BB/-
1
TRX-005 U WO 20 0 1856 MBCCH+CBCH P 1
TRX-006 U WO 22 0 1856 2
10090 30345 BTS-0025 U WO 0 0
KHAKHABYT100D BB/-
5
TRX-007 U WO 793 0 1856 MBCCH+CBCH P 0
TRX-008 U WO 851 0 1856 1
TRX-009 U WO 834 0 1857 2
TRX-010 U WO 825 0 1857 1
10090 30346 BTS-0026 U WO 0 0
KHAKHABYT230D BB/-
4
TRX-011 U WO 803 0 1857 MBCCH+CBCH P 2
TRX-012 U WO 860 0 1857 0
TRX-013 U WO 846 0 1857 1
TRX-014 U WO 844 0 1857 2
TRX-015 U WO 828 0 1857 0
TRX-016 U WO 813 0 1857 1
10090 30347 BTS-0027 U WO 0 2
KHAKHABYT340D BB/-
5
TRX-017 U WO 801 0 1352 MBCCH+CBCH P 2
TRX-018 U WO 857 0 1352 0
TRX-019 U WO 840 0 1352 1
TRX-020 U WO 838 0 1352 0
TRX-021 U WO 836 0 1352 1
TRX-022 U WO 823 0 1352 2
TRX-023 U WO 821 0 1352 0
TRX-024 U WO 817 0 1352 1
=======================================================================================
包含代码:
def GetTheSentences(infile):
with con:
cur = con.cursor()
cur.execute("DROP TABLE IF EXISTS eei")
cur.execute("CREATE TABLE eei(BCF INT, BTS INT PRIMARY KEY) ")
with open(infile) as fp:
for result_1 in re.split('BCF-', fp.read(), flags=re.UNICODE):
BCF = result_1[:4]
for result_2 in re.compile("(?=BTS-)").split(result_1):
rec = re.search('TRX-',result_2)
if rec is not None:
BTS = result_2[4:8]
print BCF + "," + BTS
我需要使用正则表达式预先将result_1拆分为与BTS相关的部分，包括"BTS-"("10090 31335 BTS-0010")之前的第13个字符，并为每个TRX拆分为result_3，但没有成功.
I need to split result_1 in BTS-related parts including 13th characters before "BTS-" ("10090 31335 BTS-0010") using regex lookahead and split to result_3 for each TRX but have no success.
请支持！
推荐答案
Python的 re.split() 不会在零长度匹配中拆分.
Python's re.split() doesn't split on zero-length matches.
因此，re.compile("(?=BTS-)").split(result_1)将永远不会分割您的字符串.您需要找到没有re.split()的解决方案，或者使用新的 regex模块.
Therefore re.compile("(?=BTS-)").split(result_1) will never split your string. You need to find a solution without re.split() or use the new regex module.
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