re.split() 给出列表中的空元素 [英] re.split() gives empty elements in list

问题描述

请帮助解决这个问题:

m = re.split('([A-Z][a-z]+)', 'PeopleRobots')打印(米)

结果:

['', '人', '', '机器人', '']

为什么列表中有空元素?

解决方案

根据 重新拆分文档:

<块引用>

如果分隔符中有捕获组并且匹配在字符串开头，结果将以空字符串开头.这字符串的结尾也是如此:

如果您想获得 People 和 Robots，请使用 re.findall:

<预><代码>>>>re.findall('([A-Z][a-z]+)', 'PeopleRobots')['人'，'机器人']

您可以省略分组:

<预><代码>>>>re.findall('[A-Z][a-z]+', 'PeopleRobots')['人'，'机器人']

please help with this case:

m = re.split('([A-Z][a-z]+)', 'PeopleRobots')
print (m)

Result:

['', 'People', '', 'Robots', '']

Why does the list have empty elements?

解决方案

According to re.split documentation:

If there are capturing groups in the separator and it matches at the start of the string, the result will start with an empty string. The same holds for the end of the string:

If you want to get People and Robots, use re.findall:

>>> re.findall('([A-Z][a-z]+)', 'PeopleRobots')
['People', 'Robots']

You can omit grouping:

>>> re.findall('[A-Z][a-z]+', 'PeopleRobots')
['People', 'Robots']

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