python re.split() 按空格、逗号和句点分割，但不是在 1,000 或 1.50 等情况下 [英] python re.split() to split by spaces, commas, and periods, but not in cases like 1,000 or 1.50

问题描述

我想使用 python re.split() 将字符串按空格、逗号和句点拆分为单个单词.但我不希望 "1,200" 被拆分成 ["1", "200"] 或 ["1.2"]拆分为["1", "2"].

I want to use python re.split() to split a string into individual words by spaces, commas and periods. But I don't want "1,200" to be split into ["1", "200"] or ["1.2"] to be split into ["1", "2"].

示例

l = "one two 3.4 5,6 seven.eight nine,ten"

结果应该是["一", "二", "3.4", "5,6", "七", "八", "九", "十"]

推荐答案

使用否定前瞻和否定后视:

Use a negative lookahead and a negative lookbehind:

> s = "one two 3.4 5,6 seven.eight nine,ten"
> parts = re.split('\s|(?<!\d)[,.](?!\d)', s)
['one', 'two', '3.4', '5,6', 'seven', 'eight', 'nine', 'ten']

换句话说，你总是用\s(空格)分割，如果not后面跟着(?!\d) 或在 (? 前加一个数字.

In other words, you always split by \s (whitespace), and only split by commas and periods if they are not followed (?!\d) or preceded (?<!\d) by a digit.

演示.

编辑:根据@verdesmarald 评论，您可能需要使用以下内容:

EDIT: As per @verdesmarald comment, you may want to use the following instead:

> s = "one two 3.4 5,6 seven.eight nine,ten,1.2,a,5"
> print re.split('\s|(?<!\d)[,.]|[,.](?!\d)', s)
['one', 'two', '3.4', '5,6', 'seven', 'eight', 'nine', 'ten', '1.2', 'a', '5']

这会将 "1.2,a,5" 拆分为 ["1.2", "a", "5"].

演示.

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