PowerShell-密码生成器-如何始终在字符串中包含数字? [英] PowerShell - Password Generator - How to always include number in string?

问题描述

我有以下PowerShell脚本，该脚本创建了一个15位随机字符串，用作Active Directory密码.

I have the following PowerShell script that creates a random string of 15 digits, for use as an Active Directory password.

麻烦的是，这在大多数情况下都有效，但是在某些情况下，它不使用数字或符号.我刚收到15封信.然后，该密码不能用作Active Directory密码，因为它必须至少包含一个数字或符号.

The trouble is, this works great most of the time, but on some occasions it doesn't use a number or symbol. I just get 15 letters. This is then not usable as an Active Directory password, as it must have at least one number or symbol in it.

$punc = 46..46
$digits = 48..57
$letters = 65..90 + 97..122
$YouShallNotPass = get-random -count 15 `
-input ($punc + $digits + $letters) |
% -begin { $aa = $null } `
-process {$aa += [char]$_} `
-end {$aa}

Write-Host "Password is $YouShallNotPass"

如何修改脚本中始终至少包含一个随机数或符号?

How would I amend the script to always have at least one random number or symbol in it?

谢谢.

推荐答案

您可以调用获取-Random cmdlet三次，每次使用不同的input参数(标点，数字和字母)，合并结果字符串并使用另一个Get-Random调用对其进行混洗:

You could invoke the Get-Random cmdlet three times, each time with a different input parameter (punc, digit and letters), concat the result strings and shuffle them using another Get-Random invoke:

 (Get-Random -Count 15 -InputObject ([char[]]$yourPassword)) -join ''

但是，为什么要重新发明轮子呢?考虑使用以下 GeneratePassword 函数:

However, why do you want to reinvent the wheel? Consider using the following GeneratePassword function:

[Reflection.Assembly]::LoadWithPartialName("System.Web")
[System.Web.Security.Membership]::GeneratePassword(15,2)

并确保至少包含一个随机数(您已经指定了符号数):

And to ensure, it contains at least one random number (you already specify the number of symbols):

do {
   $pwd = [System.Web.Security.Membership]::GeneratePassword(15,2)
} until ($pwd -match '\d')

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