为什么在这种情况下Perl可以自动生存? [英] Why does Perl autovivify in this case?
问题描述
为什么$a
成为arrayref?我什么都没推.
Why does $a
become an arrayref? I'm not pushing anything to it.
perl -MData::Dumper -e 'use strict; 1 for @$a; print Dumper $a'
$VAR1 = [];
推荐答案
这是因为for
循环将@$a
的内容视为左值,您可以将其赋值.请记住,for
将数组的内容别名为$_
.看起来即使在没有别名的内容的情况下,在@$a
中查找可别名内容的行为也足以引起自动生存.
It is because the for
loop treats contents of @$a
as lvalues--something that you can assign to. Remember that for
aliases the contents of the array to $_
. It appears that the act of looking for aliasable contents in @$a
, is sufficient to cause autovivification, even when there are no contents to alias.
这种混叠的效果也是一致的.以下还会导致自动生存:
This effect of aliasing is consistent, too. The following also lead to autovivification:
-
map {stuff} @$a;
-
grep {stuff} @$a;
-
a_subroutine( @$a);
map {stuff} @$a;
grep {stuff} @$a;
a_subroutine( @$a);
如果要管理自动生存,可以使用同义的编译指示来实现词法控件
If you want to manage autovivification, you can use the eponymous pragma to effect lexical controls.
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