在这种情况下，为什么要对原件进行分类修改? [英] Why is sorting modifing the original in this case?

问题描述

我遇到了一个问题，那就是要更改原始数组，奇怪的是，添加arr.join("...").split("...")似乎可以防止这种情况:

I had a problem that was making the original array to change, the curious thing is that adding arr.join("...").split("...") seems to prevent this:

一些背景:

• 我的脚本创建并向array
添加内容
• 此数组初始化为空，如arr=[]
• 事物通过arr[index] = "..."
添加
• 然后我想复制一份arr但已排序的
• 当我进行排序时，原始的arr被修改

• my script creates and adds stuff to an array
• this array initialized empty like arr=[]
• the things are added passing arr[index] = "..."
• then I want to have a copy of the arr but sorted
• when I do the sorting, the orignial arr is modified

这是正在发生的事情的简化版本:

Here is a simplified version of what is going on:

var arr=[], sorted;

arr[0] = "hello";
arr[1] = "world";

//buggy, the original is sorted
//sorted = arr.sort(function(a,b){return (a.length-b.length);});

sorted = arr.join("improbableCollision").split("improbableCollision").sort(function(a,b){return (a.length-b.length);});

• 为什么添加.join("*").split("*")可以解决问题?
• 是什么原因引起的问题?
• 是否有更优雅的方法来解决此问题?
• Why adding .join("*").split("*") solves the problem?
• What was causing the problem?
• Is there a more elegant way to fix this?

有关完整脚本，请检查此 jsFiddle

For the full script, check this jsFiddle

推荐答案

要在不进行所有合并和拆分的情况下进行排序，请使用slice或concat复制数组:

To sort without all that joining and splitting, copy the array with slice or concat:

var sorted = arr.slice(0).sort()

var sorted = arr.slice(0).sort()

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