Scala模板集变量 [英] Scala template set variable

问题描述

我是Scala的新手(Play 2框架中的Scala模板)，我想执行以下操作:传递参数isEdit并根据此参数定义一个值，伪代码:

I am new to Scala (Scala templates in Play 2 framework), I want to do the following: Pass a parameter isEdit and depending on this parameter, define a value, Pseudocode:

variable myTitle;

if(isEdit)
    myTitle="edit question";
else
    myTitle="create question";

如何在Play 2.0的Scala模板中制定此规则?传递isEdit并不是问题，仅创建新变量myTitle.谢谢:-)

How to formulate this in a Scala Template in Play 2.0? Passing isEdit is not the problem, only creating the new variable myTitle. Thanks :-)

推荐答案

首先，查看Playframework文档，因为那里有很多关于模板的信息. http://www.playframework.org/documentation/2.0.4/ScalaTemplates

First of all, look over the Playframework documentation as there's a lot of good info on templates there. http://www.playframework.org/documentation/2.0.4/ScalaTemplates

现在，如果需要在整个模板中重用该值，则可以在模板顶部声明它(可能在任何@import之后):

Now, if you need to reuse the value throughout the template then you can declare it at the top of your template (probably after any @imports):

@myTitle = @{ if(isEdit) "edit question" else "create question" }

如果只需要一个地方，那么实际上只需要if-else块:

If you only need it in one spot then you really just need the if-else block:

<h1>
  @if(isEdit) {
    edit question
  } else {
    create question
  }
</h1>

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