Scala 模板集变量 [英] Scala template set variable

问题描述

我是 Scala 的新手(Play 2 框架中的 Scala 模板)，我想执行以下操作:传递参数 isEdit 并根据此参数定义一个值，伪代码:

I am new to Scala (Scala templates in Play 2 framework), I want to do the following: Pass a parameter isEdit and depending on this parameter, define a value, Pseudocode:

variable myTitle;

if(isEdit)
    myTitle="edit question";
else
    myTitle="create question";

如何在 Play 2.0 的 Scala 模板中制定这个?传递 isEdit 不是问题，只是创建新变量 myTitle.谢谢:-)

How to formulate this in a Scala Template in Play 2.0? Passing isEdit is not the problem, only creating the new variable myTitle. Thanks :-)

推荐答案

首先，查看 Playframework 文档，因为那里有很多关于模板的好信息.http://www.playframework.org/documentation/2.0.4/ScalaTemplates

First of all, look over the Playframework documentation as there's a lot of good info on templates there. http://www.playframework.org/documentation/2.0.4/ScalaTemplates

现在，如果您需要在整个模板中重复使用该值，那么您可以在模板的顶部(可能在任何@imports 之后)声明它:

Now, if you need to reuse the value throughout the template then you can declare it at the top of your template (probably after any @imports):

@myTitle = @{ if(isEdit) "edit question" else "create question" }

如果你只需要一个地方，那么你真的只需要 if-else 块:

If you only need it in one spot then you really just need the if-else block:

<h1>
  @if(isEdit) {
    edit question
  } else {
    create question
  }
</h1>

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