指向整数数组的指针 [英] Pointer to an array of ints

问题描述

两者之间有什么区别

//Example of "Complicated Array Declarations" from C++ Primer
int arr[10] = {1,2,3,4,5,6,7,8,9,10};
int (*Parr)[10] = &arr;

并且:

int arr[10] = {1,2,3,4,5,6,7,8,9,10};
int *Parr = arr;

都是指向整数数组的指针.但是为了访问第一个代码段中的arr的第一个元素，我必须执行**Parr，而在第二个代码段中，我只需要取消引用一次*Parr

Both are pointers to an array of integers. But in order to access the first element of arr in the first snippet, I have to do **Parr whereas in the second, I only have to dereference once *Parr

推荐答案

在第一个代码示例中，

int (*Parr)[10] = &arr;

Parr是指向10个整数的数组的指针.它只能指向这样的对象.例如，

Parr is a pointer to an array of 10 ints. It can only point to such an object. For example,

int (*Parr)[10];
int a[10];
Parr = &a; // OK
int b[42];
Parr = &b; // ERROR, b is of the wrong type

在第二个代码示例中，

int *Parr = arr;

Parr是指向int的指针，已初始化为指向arr的第一个元素.但是它可以指向任何int.

Parr is a pointer to int, initialized to point to the first element of arr. But it can point to any int.

int* Parr;
int a[10];
Parr = &a; // OK, a decays to int*
int b[42];
Parr = &b; // OK, b decays to int*
int c = 42;
Parr = &c; // OK, c is an int*

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