投无效指针指向整数数组 [英] Cast void pointer to integer array

问题描述

我有一个问题，我有一个指向内存区域。我想利用这个指针来创建一个整数数组。

I have a problem where I have a pointer to an area in memory. I would like to use this pointer to create an integer array.

本质上讲，这是我，一个指针大小的内存地址100 * 300 * 2 = 60000字节

Essentially this is what I have, a pointer to a memory address of size 100*300*2 = 60000 bytes

unsigned char *ptr = 0x00000000; // fictional point in memory goes up to 0x0000EA60

我想实现的是考察这个内存大小的整型数组100 * 150 = 15000整数= 60000字节，是这样的：

What i would like to achieve is to examine this memory as an integer array of size 100*150 = 15000 ints = 60000 bytes, like this:

unsigned int array[ 100 ][ 150 ];

我假设它涉及到一些铸造虽然我不知道究竟是如何制定的。任何帮助将是AP preciated。

I'm assuming it involves some casting though i'm not sure exactly how to formulate it. Any help would be appreciated.

推荐答案

您可以将指针转换为无符号整数（*）[150] 。然后，它可以被用来如同这是一个二维数组（好像，因为sizeof的 的行为是不同的）。

You can cast the pointer to unsigned int (*)[150]. It can then be used as if it is a 2D array ("as if", since behavior of sizeof is different).

unsigned int (*array)[150] = (unsigned int (*)[150]) ptr;

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