如何将Boost数组表示为类型的指针? [英] How to represent boost array as a pointer of a type?

问题描述

我将boost数组用作缓冲区，并希望将其作为参数传递给函数.我想要传递的方式是将大小确定为另一个参数，以便我可以传递大小不同的缓冲区.目前，我的代码如下:

I'm using a boost array as a buffer and wanted to pass it on as an argument to a function. The way I would like to pass it is so that the size is determined as another argument so that I can pass over buffers of varying sizes. Currently, my code is as follows:

void DataTransform(boost::array<char, 1024> data) {
    //do something
}

使用普通数组我可以使用:

With a normal array I could have just used:

void DataTransform(char* data, uint_16 size) {
    //do something
}

我将如何解开boost数组以将其表示为指针?

How would I go about unwrapping the boost array to represent it as a pointer?

推荐答案

boost::array具有data()

boost::array has a data() method that returns a pointer to the start of the array, and a size() method that returns the number of elements in the array:

DataTransform(some_array.data(), some_array.size())

另一种选择是对DataTransform方法进行重做以在迭代器上工作:

Another option is to rework your DataTransform method to work on iterators:

template<typename T, typename U>
DataTransform(T begin, U end) {
    for(; begin != end; ++begin) {
        // do something with *begin
    }
}

然后您可以这样称呼它:

And then you can call it like so:

DataTransform(std::begin(some_array), std::end(some_array))
DataTransform(some_c_array, some_c_array + some_c_array_size)
DataTransform(std::begin(some_list), std::end(some_list))

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