postgres array_agg错误:无法累积不同维数的数组 [英] postgres array_agg ERROR: cannot accumulate arrays of different dimensionality

问题描述

我在postgresql中有一个包裹表，其中zoning和zoning_description列被array_agg转换为文本. new.universities表具有9行，我需要在输出中返回9行.

I have a parcels table in postgresql in which the zoning and zoning_description columns are array_agg cast over to text. the new.universities table has 9 rows and I need to return 9 rows in the output.

此查询的目的是查找这些大学所在的所有属性，并将这些区域的类型折叠为1个唯一的列，并将其几何合并/分解为多面体

The purpose of this query is to find all the properties these universities are located on and collapse there zoning types into 1 unique column and union/dissolve their geometries into multipolygons

select array_agg(distinct dp.zoning) zoning,array_agg(distinct dp.zoning_description) zoning_description,
    uni.school name_,uni.address,'University' type_,1000 buff,st_union(dp.geom) 
from new.universities uni join new.detroit_parcels_update dp
on st_intersects(st_buffer(uni.geom,-10),dp.geom)
group by name_,uni.address,type_,buff

我收到此错误

ERROR:  cannot accumulate arrays of different dimensionality
********** Error **********

ERROR: cannot accumulate arrays of different dimensionality
SQL state: 2202E

我可以执行array_agg(distinct dp.zoning :: text)分区等.但是这会返回一个完全混乱的列，其中包含数组中的嵌套数组...

I can do array_agg(distinct dp.zoning::text) zoning etc.. but this returns a completely messed up column with nested arrays in arrays...

根据这里的答案，我的更新查询不起作用

Based on the answer here is my updated query which does not work

select array_agg(distinct zoning_u) zoning,array_agg(distinct zoning_description_u) zoning_description,
        uni.school name_,uni.address,'University' type_,1000::int buff,st_union(dp.geom) geom
from new.detroit_parcels_update dp,unnest(zoning) zoning_u,
unnest(zoning_description) zoning_description_u
join new.universities uni
on st_intersects(st_buffer(uni.geom,-10),dp.geom)
group by name_,uni.address,type_,buff order by name_

遇到此错误

ERROR:  invalid reference to FROM-clause entry for table "dp"
LINE 6: on st_intersects(st_buffer(uni.geom,-10),dp.geom)
                                                 ^
HINT:  There is an entry for table "dp", but it cannot be referenced from this part of the query.

********** Error **********

ERROR: invalid reference to FROM-clause entry for table "dp"
SQL state: 42P01
Hint: There is an entry for table "dp", but it cannot be referenced from this part of the query.
Character: 373

我最后的有效查询是

with t as(select dp.zoning,dp.zoning_description,uni.school name_,uni.address,'University' type_,1000::int buff,st_union(dp.geom) geom
    from new.detroit_parcels_update dp
    join new.universities uni
    on st_intersects(st_buffer(uni.geom,-10),dp.geom)
    group by name_,uni.address,type_,buff,dp.zoning,zoning_description order by name_
    )
select name_,address,type_,buff,st_union(geom) geom,array_agg(distinct z) zoning, array_agg(distinct zd) zoning_description
from t,unnest(zoning) z,unnest(zoning_description) zd 
group by name_,address,type_,buff

推荐答案

示例数据:

create table my_table(name text, numbers text[], letters text[]);
insert into my_table values
    ('first',  '{1, 2}', '{a}'   ),
    ('first',  '{2, 3}', '{a, b}'),
    ('second', '{4}',    '{c, d}'),
    ('second', '{5, 6}', '{c}'   );

您应该聚合数组元素，而不是数组.使用unnest():

You should aggregate arrays elements, not arrays. Use unnest():

select 
    name, 
    array_agg(distinct number) as numbers, 
    array_agg(distinct letter) as letters
from 
    my_table, 
    unnest(numbers) as number, 
    unnest(letters) as letter
group by name;

  name  | numbers | letters 
--------+---------+---------
 first  | {1,2,3} | {a,b}
 second | {4,5,6} | {c,d}
(2 rows)    

或者，您可以创建一个自定义聚合.您需要一个函数来合并数组(删除重复项并置):

Alternatively, you can create a custom aggregate. You need a function to merge arrays (concatenation with duplicates removing):

create or replace function public.array_merge(arr1 anyarray, arr2 anyarray)
    returns anyarray language sql immutable
as $$
    select array_agg(distinct elem order by elem)
    from (
        select unnest(arr1) elem 
        union
        select unnest(arr2)
    ) s
$$;

create aggregate array_merge_agg(anyarray) (
    sfunc = array_merge,
    stype = anyarray
);

select 
    name, 
    array_merge_agg(numbers) as numbers, 
    array_merge_agg(letters) as letters
from my_table
group by name;

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