使用SQLAlchemy计算POSTGRES中的DATEDIFF [英] Calculate DATEDIFF in POSTGRES using SQLAlchemy

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本文介绍了使用SQLAlchemy计算POSTGRES中的DATEDIFF的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要在几分钟内计算 DATEDIFF 时间戳类型的两列之间。
网上有很多简单的示例,但是使用psycopg2 + sqlalchemy时,它们都无法正常工作。
我尝试过:

I need to calculate DATEDIFF in minutes between 2 columns of timestamp type. There are so many simple examples on the web, but none of them work really much properly using psycopg2 + sqlalchemy. I've tried:

from sqlalchemy import as sa
from datetime import datetime

# con is a standard pool of connections :class:Connection
con.execute(
    sa.func.datediff(
        sa.literal_column('minute'),
        datetime.utcnow(),
        datetime.utcnow(),
    )
)

它抛出:

sqlalchemy.exc.ProgrammingError: (psycopg2.ProgrammingError) column "minute" does not exist
LINE 1: SELECT datediff(minute, '2017-02-27T15:04:33.217559'::timest...
                    ^
[SQL: 'SELECT datediff(minute, %(datediff_2)s, %(datediff_3)s) AS datediff_1'] [parameters: {'datediff_3': datetime.datetime(2017, 2, 27, 15, 4, 33, 217596), 'datediff_2': datetime.datetime(2017, 2, 27, 15, 4, 33, 217559)}]

如果我尝试:

con.execute(
    sa.func.datediff(
        'minute',
        datetime.utcnow(),
        datetime.utcnow(),
    )
)

我收到:

sqlalchemy.exc.ProgrammingError: (psycopg2.ProgrammingError) function datediff(unknown, timestamp without time zone, timestamp without time zone) does not exist
LINE 1: SELECT datediff('minute', '2017-02-27T12:27:49.369724'::time...
           ^
HINT:  No function matches the given name and argument types. You might need to add explicit type casts.
[SQL: 'SELECT datediff(%(datediff_2)s, %(datediff_3)s, %(datediff_4)s) AS datediff_1'] [parameters: {'datediff_4': datetime.datetime(2017, 2, 27, 12, 27, 49, 369740), 'datediff_2': 'minute', 'datediff_3': datetime.datetime(2017, 2, 27, 12, 27, 49, 369724)}]

任何想法如何使其正确?

Any ideas how to make it right?

推荐答案

PostgreSQL没有 datediff 函数。要获取分钟数,请使用SQL表达式

trunc((extract(epoch FROM newer_date) - extract(epoch FROM older_date)) / 60)




  • extract(epoch FROM…) 将时间戳转换为秒数。

  • / 60 转换为秒到分钟

  • trunc (…)除去小数部分。

    • extract(epoch FROM …) converts the timestamp to number of seconds.
    • / 60 converts to seconds to minutes
    • trunc(…) removes the fractional part.
    • 所以可能尝试

      sa.func.trunc((
          sa.extract('epoch', datetime.utcnow()) -
          sa.extract('epoch', datetime.utcnow())
      ) / 60)
      

      这篇关于使用SQLAlchemy计算POSTGRES中的DATEDIFF的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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