在64位OS X 10.6上制作胖二进制文件的正确方法是选择32位? [英] Proper way to make a fat binary prefer to be 32bit on 64bit OS X 10.6?
问题描述
假设我问用户您想以32位模式还是64位模式运行,他们选择了32位。如何在操作系统中注册此事实?我查看了 arch 命令,但我不想编写包裹二进制文件的脚本。我怀疑有一种plist-y方法可以做到这一点,但是我找不到文档(除了arch)。
Suppose I ask the user "do you want to run in 32bit mode or 64bit mode" and they pick 32bit. How do I register this fact with the operating system? I've looked at the arch command, but I don't want to have to write a script that wraps the binary. I suspect there is a plist-y way to do this, but I can't find documentation (other than arch).
推荐答案
尝试使用此 Info.plist
键, LSArchitecturePriority
:
Try using this Info.plist
key, LSArchitecturePriority
:
<key>LSArchitecturePriority</key>
<array>
<string>i386</string>
<string>x86_64</string>
<string>ppc</string>
<string>ppc64</string>
</array>
不要通过动态更改程序包来做到这一点。运行您的程序的用户可能无权对其进行写入。如果需要基于每个用户执行此操作,则最好使用包装脚本。
Just don't do this by dynamically altering your program's bundle. The user running your program might not have permission to write to it. If you need to do this on a per-user basis, a wrapper script would be a preferred alternative.
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