python中的输入异常 [英] exception in input in python

问题描述

运行以下代码时：

try:
   key=int(input())
except ValueError as string:
   print("Error is within:",string)

例如，如果将'rrr'放进去，则会出现此异常，因为'rrr'不支持（int）

for example, if one puts 'rrr' this exception will rise, since 'rrr' does not support (int)

： int（）的无效文字，基数为10：'rrr'

However, instead ot putting the actual string, it puts: "invalid literal for int() with base 10: 'rrr' "

我如何使其工作，以便变量'string'实际得到错误的输入，用户给出的（在此示例中，我希望它打印：错误在rrr内）

How do I make it work so that the variable 'string' actually gets the wrong input that the user gave (in this example, I want it to print: 'Error is within: rrr')

非常感谢

推荐答案

您的问题来自以下事实：变量 string 是ValueError异常的错误消息。如果您想打印出用户的无效输入，则需要创建一个变量来存储用户的输入，然后再尝试/例外。例如：

Your issue comes from the fact that the variable string is the error message for a ValueError exception. If you wanted to print out the user's invalid input, you would need to create a variable that stores the user's input before your try/except. For example:

userInput = input()
try:
   key=int(userInput)
except ValueError:
   print("Error is within:",userInput)

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