在python中异常执行异常 [英] unexpected execution of Exceptions in python
问题描述
import sys
def menu():
打印计算器使用功能
打印选择您的选项:
打印
打印1)加号
打印2)减法
打印3)乘法
打印4)分区
打印5)退出calculator.py
打印
返回输入(选择您的选项:)
def add(a,b):
try:
print a,+,b,=,a + b
打印你要继续吗?
decision = raw_input(yes or no:)
如果决定=='否'或决定=='n':
return(你已退出)
sys.exit(0)
elif决定=='是'或决定=='y':
menu()
untrusted.execute()
除了:
打印错误选择!!!
e = sys.exc_info()[0]
打印错误:%s%e
sys.exit(0)
这适用于我....我想, return(你已经退出)
是这里的问题,istead的 sys.exit(0)
try return 0
我不知道为什么它的一个问题,但它的作品。我尝试了是的,没有条件。
import sys
$ d
打印使用功能的计算器
打印选择您的选项:
print
print1)加法
print2)减法
print3)乘法
print4)分区
print5)退出calculator.py
print
返回输入(选择你的选项)
def add(a,b):
try:
print a,+, b,=,a + b
打印你要继续吗?
decision = raw_input(yes or no:)
如果决定=='否'或决定=='n':
returnn
#sys.exit(0)
elif decision =='yes'或决定=='y':
return y
untrusted.execute()
除了:
打印错误选择!!!
e = sys.exc_info()[0]
打印错误:%s%e
sys.exit(0)
while(True) b $ b selected_option = menu()
if(selected_option == 1):
print输入第一个数字:
no1 = raw_input()
print输入第二个数字:
no2 = raw_input()
option = add(no1,no2)
if(option =='y'):
printyes selected
continue
if(option =='n'):
printno selected
sys.exit(0)
输出:
是否要继续:
是或否:re
错误选择!!!
错误:< type'exceptions.NameError'>
是否要继续:
是或否:y
是选择
使用函数的计算器
选择您的选项:
1)加法
2)减法
3)乘法
4)部门
5)退出calculator.py
选择您的选项:
您是否要继续:
是或否:n
没有选择
root @ yogesh-System-model:〜#
I am novice to python and i came up with this problem. i have made a simple program for calculator. In add function, i have used try- except. when this line is encountered (if decide== 'no' or decide== 'n':), it displays the print line "return(" You have exited ")" but it also throws the exception. I cant understand why.
import sys
def menu():
print "calculator using functions"
print "Choose your option:"
print " "
print "1) Addition"
print "2) Subtraction"
print "3) Multiplication"
print "4) Division"
print "5) Quit calculator.py"
print " "
return input ("Choose your option: ")
def add(a,b):
try:
print a, "+", b, "=", a + b
print " Do you want to continue: "
decide=raw_input("yes or no: ")
if decide== 'no' or decide== 'n':
return(" You have exited ")
sys.exit(0)
elif decide=='yes' or decide== 'y':
menu()
untrusted.execute()
except:
print "wrong choice!!!"
e = sys.exc_info()[0]
print "Error: %s" % e
sys.exit(0)
This works for me ....I suppose return(" You have exited ")
is problem here and istead of sys.exit(0)
try return 0
I dont know why its a problem but it works. I tried it for both yes and no conditions.
import sys
def menu():
print "calculator using functions"
print "Choose your option:"
print " "
print "1) Addition"
print "2) Subtraction"
print "3) Multiplication"
print "4) Division"
print "5) Quit calculator.py"
print " "
return input ("Choose your option: ")
def add(a,b):
try:
print a, "+", b, "=", a + b
print " Do you want to continue: "
decide=raw_input("yes or no: ")
if decide== 'no' or decide== 'n':
return "n"
#sys.exit(0)
elif decide=='yes' or decide== 'y':
return "y"
untrusted.execute()
except:
print "wrong choice!!!"
e = sys.exc_info()[0]
print "Error: %s" % e
sys.exit(0)
while(True):
selected_option=menu()
if(selected_option == 1):
print "Enter first number:"
no1 = raw_input()
print "Enter second number:"
no2 = raw_input()
option=add(no1,no2)
if(option == 'y'):
print "yes selected"
continue
if(option=='n'):
print "no selected"
sys.exit(0)
output: Do you want to continue:
yes or no: re
wrong choice!!!
Error: <type 'exceptions.NameError'>
Do you want to continue:
yes or no: y
yes selected
calculator using functions
Choose your option:
1) Addition 2) Subtraction 3) Multiplication 4) Division 5) Quit calculator.py
Choose your option:
Do you want to continue:
yes or no: n
no selected
root@yogesh-System-model:~#
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