如何在Python中将元组作为参数传递? [英] How to pass tuple as argument in Python?

问题描述

假设我想要一个元组列表.这是我的第一个主意:

Suppose I want a list of tuples. Here's my first idea:

li = []
li.append(3, 'three')

这将导致:

Traceback (most recent call last):
  File "./foo.py", line 12, in <module>
    li.append('three', 3)
TypeError: append() takes exactly one argument (2 given)

所以我求助于:

li = []
item = 3, 'three'
li.append(item)

有效，但似乎过于冗长.有更好的方法吗?

which works, but seems overly verbose. Is there a better way?

推荐答案

添加更多括号:

li.append((3, 'three'))

带有逗号的括号会创建一个元组，除非它是参数列表.

Parentheses with a comma create a tuple, unless it's a list of arguments.

这意味着:

()    # this is a 0-length tuple
(1,)  # this is a tuple containing "1"
1,    # this is a tuple containing "1"
(1)   # this is number one - it's exactly the same as:
1     # also number one
(1,2) # tuple with 2 elements
1,2   # tuple with 2 elements

长度为0的元组也会发生类似的情况:

A similar effect happens with 0-length tuple:

type() # <- missing argument
type(()) # returns <type 'tuple'>

这篇关于如何在Python中将元组作为参数传递?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！