如何在python中将字典项作为函数参数传递? [英] How to pass dictionary items as function arguments in python?

问题描述

我的代码

第一个文件:

data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}
my_function(*data)

第二个文件:

my_function(*data):
    schoolname  = school
    cityname = city
    standard = standard
    studentname = name

在上面的代码中，只有数据"字典的键被传递给my_function()，但我想要传递键值对.如何纠正?

in the above code, only keys of "data" dictionary were get passed to my_function(), but i want key-value pairs to pass. How to correct this ?

我希望 my_function() 像这样修改

my_function(school='DAV', standard='7', name='abc', city='delhi')

这是我的要求，根据这个给出答案

and this is my requirement, give answers according to this

字典键 class 更改为 standard

dictionary key class is changed to standard

推荐答案

如果你想像这样使用它们，请像往常一样用变量名定义函数:

If you want to use them like that, define the function with the variable names as normal:

def my_function(school, standard, city, name):
    schoolName  = school
    cityName = city
    standardName = standard
    studentName = name

现在您可以在调用函数时使用**:

Now you can use ** when you call the function:

data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}

my_function(**data)

它会如你所愿.

P.S. 不要使用保留字，例如 class.(例如，使用 klass 代替)

P.S. Don't use reserved words such as class.(e.g., use klass instead)

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