如何在ctypes python中将char指针作为参数传递 [英] how to pass char pointer as argument in ctypes python

问题描述

请帮助我将下面的c ++代码行转换为python ctypes类型：

Please help me in converting below line of c++ code into ctypes python:

Ret = openFcn(&Handle, "C:\\Config.xml");

以下是每个声明：

typedef uint16_t (* OpenDLLFcnP)(void **, const char *);
OpenDLLFcnP openFcn = NULL;
openFcn = (OpenDLLFcnP) myLibrary.resolve("Open");
void *Handle = NULL;

推荐答案

myLibrary.resolve 是未定义的，但是您需要的常规代码（未调试）是：

myLibrary.resolve is undefined, but the general code you need (untested) is:

import ctypes
dll = ctypes.CDLL('your.dll')
Open = dll.Open
Open.argtypes = [ctypes.POINTER(ctypes.c_void_p),ctypes.c_char_p]
Open.restype = ctypes.c_uint16
Handle = ctypes.c_void_p()
result = Open(ctypes.byref(Handle),'c:\\Config.xml')

这假设您有一个名为 your.dll 的DLL，其功能为打开您要呼叫的电话。

This assumes you have a DLL named your.dll with a function Open you want to call.

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