从python列表中获取值序列 [英] Take sequence of values from a python list

问题描述

我有一个这样的数组，

a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]

我想列出小于7的值(如下所示)

and I want to make list of values that are lesser than 7 (look like following)

b = [[3,2,5],[4,5,6,3],[4,5],[5],[4],[6]]

所以我使用了以下方法，

So I used following method,

>>> from itertools import takewhile
>>> a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
>>>list(takewhile(lambda x: x < 7 , a))
[3, 2, 5]

但是我只得到第一个序列.谁能帮我解决这个问题? 谢谢你.

But I only get the first sequence. Can anyone help me to solve this problem ? Thank you.

推荐答案

a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
from itertools import groupby
[list(g) for k, g in groupby(a, lambda x:x<7) if k]

输出:

[[3, 2, 5], [4, 5, 6, 3], [4, 5], [5], [4], [6]]

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