将列表合并成元组对(x，y) [英] Combine a list into tuple pairs (x, y)

问题描述

我正在尝试合并通过sys.argv传入的数字对. 示例:

I'm trying to combine pairs of numbers passed in via sys.argv. Example:

python myscript.py -35.12323 112.76767 -36.33345 112.76890 -33.68689 111.8980

我的目标是将它们转换为元组中的二进制数集. 像这样:

My goal would be to turn these into sets of two's in tuples. Like such:

((-35.12323,112.76767),(-36.33345,112.76890),(-33.68689,111.8980))

到目前为止，这是我一直在尝试的方法，但是当我将结果传递给Shapely Point和Polygon方法时，会遇到问题.

This is what I've tried to so far, but it has a problem when I pass the results to the Shapely Point and Polygon methods.

from shapely.geometry import Polygon
from shapely.geometry import Point
import sys

def args_to_tuple(list):
    arglist = []

    for coord in list:
        arglist.append(float(coord))

    i = 0
    polylist = []

    for xory in arglist:
        tmp = (arglist[i],arglist[i+1])
        polylist.append(tmp)

    return tuple(polylist)


poly = Polygon(args_to_tuple(sys.argv[3:]))

# xy pair for point is first two sys args
point = Point(args_to_tuple(sys.argv[1:3]))

print point.within(poly) # should result in true, but doesn't
print poly.contains(point) # should result in true, but doesn't

这似乎在itertools中很常见，但是我似乎无法在该模块中找到让您成对抓取物品的任何东西.

It seems like this would be something common in itertools, but I can't seem to find anything in that module that lets you grab items in a pair.

推荐答案

In [10]: args_str = '-35.12323 112.76767 -36.33345 112.76890 -33.68689 111.8980'

In [11]: args = map(float, args_str.split())

In [12]: args
Out[12]: [-35.12323, 112.76767, -36.33345, 112.7689, -33.68689, 111.898]

In [13]: zip(args[::2], args[1::2])
Out[13]: [(-35.12323, 112.76767), (-36.33345, 112.7689), (-33.68689, 111.898)]

zip可以替换为 itertools.izip 会产生一个迭代器而不是列表.

zip can be replaced with itertools.izip which produces an iterator instead of a list.

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