如何从链表中删除节点? [英] How to delete node from linked list?
本文介绍了如何从链表中删除节点?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
将整数添加到列表中可以很好地工作,但是删除和打印时出了点问题.
Adding integers to list works fine, but there's something wrong with deleting and printing.
我对调试器还不友好,但是我发现节点指针"first"存在错误.它的值为-17891602.我不知道发生了什么事...
I'm not friendly with debugger yet, but I found out that there is error from node pointer 'first'. Its value is -17891602. I don't know what happened...
#include <iostream>
using namespace std;
class nodeList;
class node {
friend class nodeList;
private:
int data;
node* link;
public:
node() { //constructor
data = 0;
link = NULL;
}
node(int d) { //constructor
data = d;
link = NULL;
}
node(int d, node* l){ //constructor
data = d;
link = l;
}
};
class nodeList {
private:
node* first;
int num = 0;
node* nt;
public:
nodeList() {
first = new node();
}
node* end(node* t){ //return pointer of last element
t = first;
for (int i = 0; i < num; i++){
t = t->link;
}
return t;
}
void add(int a){ //add 'a' at the end of the list
node* x = new node(a);
node* y = this->end(nt);
y->link = x;
num++;
}
void del(int n){ //n : data of element that you want to delete from list
node* temp = first;
node* pretemp = NULL;
node* x;
int i;
for (i = 0; i <= this->num; i++){ //loop to find 'n'
pretemp = temp;
temp = temp->link;
if (n == temp->data){
break;
}
}
temp = first;
for (int j = 0; j<i; j++){ //i : where 'n' is,
temp = temp->link;
}
x = temp->link;
pretemp->link = x;
delete temp;
num--;
}
void printList(){
node* temp = first;
temp = temp->link;
for (int i = 0; i<this->num; i++){
cout << temp->data << endl;
temp = temp->link;
}
}
};
int main(){
nodeList *l = new nodeList();
int a;
int select;
while (1){
cout << "1. ADD 2. DELETE 3. PRINT" << endl;
cin >> select;
if (select == 1){
cout << "Enter an integer: ";
cin >> a;
if (cin.fail()) {
cout << "Wrong input" << endl;
break;
}
l->add(a);
l->printList();
}
if (select == 2){
cout << "Enter the data of the element you want to delete: ";
cin >> a;
if (cin.fail()) {
cout << "Wrong input" << endl;
break;
}
l->del(a);
l->printList();
}
if (select == 3){
l->printList();
}
}
}
推荐答案
您的del
函数将删除临时节点(需要删除的节点之前的节点).
Your del
function deletes pretemp node (node that was before the one that you need to delete).
可能的解决方法:
//n : data of element that you want to delete from list
void del(int n)
{
//loop to find 'n'
for (node *tmp = first; tmp->link; tmp = tmp->link)
{
if (n == tmp->link->data)
{
node *x = tmp->link;
tmp->link = tmp->link->link;
delete x;
num--;
break;
}
}
}
还,您的del
是否应该删除所有data
== n
的节点?
Also, was your del
supposed to delete all nodes with data
== n
?
这篇关于如何从链表中删除节点?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
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