从数组列表中随机选择5个元素，而无需重复元素 [英] Randomly select 5 elements from an array list without repeating an element

问题描述

我目前正在尝试为iOS开发一个应用程序，但是我无法获得一些简单的代码.基本上，我需要从数组列表中随机选择5个元素，而无需重复一个元素.我有一个草稿，但只显示一个元素.

I am currently trying to make an app for iOS but I can't get some simple code down. Basically I need to randomly select 5 elements from an array list without repeating an element. I have a rough draft, but it only displays one element.

这是我的代码:

let array1 = ["salmon", "turkey", "salad", "curry", "sushi", "pizza"]

let randomIndex1 = Int(arc4random_uniform(UInt32(array1.count)))

print(array1[randomIndex1])

推荐答案

您可以这样做:

let array1 = ["salmon", "turkey", "salad", "curry", "sushi", "pizza", "curry", "sushi", "pizza"]
var resultSet = Set<String>()

while resultSet.count < 5 {
    let randomIndex = Int(arc4random_uniform(UInt32(array1.count)))
    resultSet.insert(array1[randomIndex])
}

let resultArray = Array(resultSet)

print(resultArray)

set只能包含唯一元素，因此同一元素不能超过一次.

A set can contain unique elements only, so it can't have the same element more than once.

我创建了一个空的set，然后只要该数组包含少于5个元素(您选择的数字)，我就会对其进行迭代并向set添加一个随机元素.

I created an empty set, then as long as the array contains less than 5 elements (the number you chose), I iterated and added a random element to the set.

在最后一步，我们需要将集合转换为数组以获得所需的数组.

In the last step, we need to convert the set to an array to get the array that you want.

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