如何在python中制作螺旋状螺旋形? [英] How do I make make spiral in python?
问题描述
我想制作一个给它一个数字的函数,并且该函数返回从1到该数字的螺旋形(在二维数组中).例如,如果将数字25赋予函数,它将返回类似以下内容的内容:
我尝试了不同的方法,但没有解决.我只是想不通.
希望我能正确地解释自己.
I want to make a function that I give it a number and the function returns a spiral from 1 to that number(in 2 dimensional array). For example if I give the number 25 to the function it will return something like this:
I tried different ways but nothing worked out. I just cant figure it out.
Hope I explained myself properly.
推荐答案
这里的问题主要是枚举坐标之一-将数字与坐标匹配,然后根据需要打印出来.
Mostly the issue here is one of enumerating coordinates - match numbers to coordinates, then print it out however you want.
首先要注意两种基本模式:
Start by noticing the two fundamental patterns:
- (方向)向右移动,然后向下移动,然后向左移动,然后向上移动,然后...(希望这很明显)
- (幅值)先移动一次,然后移动一,然后移动两个,然后移动两个,然后移动三个...
因此,使用这些规则,编写一个生成number, coordinates
元组的生成器.
So with those rules, write a generator that yields number, coordinates
tuples.
最明显的是,如果您首先设置一些帮助程序功能;我会特别冗长:
It's clearest if you set up some helper functions first; I'll be extra verbose:
def move_right(x,y):
return x+1, y
def move_down(x,y):
return x,y-1
def move_left(x,y):
return x-1,y
def move_up(x,y):
return x,y+1
moves = [move_right, move_down, move_left, move_up]
现在很容易了,生成器:
Easy enough, now the generator:
def gen_points(end):
from itertools import cycle
_moves = cycle(moves)
n = 1
pos = 0,0
times_to_move = 1
yield n,pos
while True:
for _ in range(2):
move = next(_moves)
for _ in range(times_to_move):
if n >= end:
return
pos = move(*pos)
n+=1
yield n,pos
times_to_move+=1
演示:
list(gen_points(25))
Out[59]:
[(1, (0, 0)),
(2, (1, 0)),
(3, (1, -1)),
(4, (0, -1)),
(5, (-1, -1)),
(6, (-1, 0)),
(7, (-1, 1)),
(8, (0, 1)),
(9, (1, 1)),
(10, (2, 1)),
(11, (2, 0)),
(12, (2, -1)),
(13, (2, -2)),
(14, (1, -2)),
(15, (0, -2)),
(16, (-1, -2)),
(17, (-2, -2)),
(18, (-2, -1)),
(19, (-2, 0)),
(20, (-2, 1)),
(21, (-2, 2)),
(22, (-1, 2)),
(23, (0, 2)),
(24, (1, 2)),
(25, (2, 2))]
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