是否可以在没有预先定义的情况下将结构变量作为函数参数传递? [英] Is it possible to pass a structure variable as a function argument without previously defining it?

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问题描述

我有两个这样定义的结构(在color.h中):

I have two structs defined as so (in color.h):

typedef struct rgb {
  uint8_t r, g, b;
} rgb;

typedef struct hsv {
  float h, s, v;
} hsv;

hsv rgb2hsv(rgb color);
rgb hsv2rgb(hsv color);

然后我在main.c中具有以下功能:

I then have the following in main.c which works:

hsv hsvCol = {i/255.0, 1, 1};
rgb col = hsv2rgb(hsvCol);

我希望能够仅在hsv2rgb的参数内创建变量hsvCol,而不必创建变量并将其作为参数传递.

I want to be able to just create the variable hsvCol inside the parameters for hsv2rgb without having to create the variable and passing it as a parameter.

我已经尝试了以下每一项(代替上面的两行),可惜的是它们都没有编译:(

I've tried the each of the following (in place of the two lines above), sadly none of which compile :(

rgb col = hsv2rgb({i/255.0, 1, 1});
rgb col = hsv2rgb(hsv {i/255.0, 1, 1});
rgb col = hsv2rgb(hsv hsvCol {i/255.0, 1, 1})
rgb col = hsv2rgb(struct hsv {i/255.0, 1, 1});

我的问题是:

  1. 我可以完全做我想做的事情吗(但显然以另一种方式)?

  1. Can I do what I was trying to do at all (but obviously in a different way)?

如果为1,我该怎么做?

If 1, how do I go about doing so?

推荐答案

您可以使用复合文字.

引用C11,第6.5.2.5节,第3段,

Quoting C11, chapter §6.5.2.5, paragraph 3,

一个后缀表达式,该表达式由带括号的类型名称和大括号括起来 初始化程序列表是一个复合文字.它提供了一个未命名的对象,其值由初始值设定项列表给出.

A postfix expression that consists of a parenthesized type name followed by a brace enclosed list of initializers is a compound literal. It provides an unnamed object whose value is given by the initializer list.

以及第5段,

复合文字的值是由初始化的未命名对象的值. 初始化列表. [...]

The value of the compound literal is that of an unnamed object initialized by the initializer list. [...]

因此,在您的情况下,类似的代码

So, in your case, the code like

hsv hsvCol = {i/255.0, 1, 1};
rgb col = hsv2rgb(hsvCol);

可以改写为

rgb col = hsv2rgb( ( hsv ) {i/255.0, 1, 1} );
                    ^^^^    ^^^^^^^^^^^^^
                    |             |
                    |              -- brace enclosed list of initializers
                    -- parenthesized type name

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