通过串联另一个char *来初始化const char * [英] Initialize const char* by concatenating another char*

问题描述

我要重构:

const char* arr = 
  "The "
  "quick "
  "brown";

变成这样:

const char* quick = "quick ";
const char* arr = 
  "The "
  quick
  "brown";

因为在许多其他地方都使用了字符串"quick".理想情况下，我只需要能够使用const基本类型来做到这一点，所以就不需要字符串.最好的方法是什么?

because the string "quick" is used is many other places. Ideally I need to be able to do this with just const primitive types, so no string. What is the best way to do this?

推荐答案

以答案的形式编译注释:

Compiling the comments in the form of an answer:

1. 使用宏.

1. Use a macro.

#define QUICK "quick "

char const* arr = "The " QUICK "brown";

使用std:string.

std::string quick = "quick ";
std::string arr = std::string("The ") + quick + "brown";

工作代码:

#include <iostream>
#include <string>

#define QUICK "quick "

void test1()
{
   char const* arr = "The " QUICK "brown";
   std::cout << arr << std::endl;
}

void test2()
{
   std::string quick = "quick ";
   std::string arr = std::string("The ") + quick + "brown";
   std::cout << arr << std::endl;
}

int main()
{
   test1();
   test2();
}

输出:

The quick brown
The quick brown

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