C ++-如何重设输出流操纵器标志 [英] C++ - How to reset the output stream manipulator flags

问题描述

我有一行代码将填充值设置为输出中的-"字符，但需要将setfill标志重置为其默认的空白字符.我该怎么办?

I've got a line of code that sets the fill value to a '-' character in my output, but need to reset the setfill flag to its default whitespace character. How do I do that?

cout << setw(14) << "  CHARGE/ROOM" << endl;
cout << setfill('-') << setw(11) << '-' << "  " << setw(15) << '-' << "   " << setw(11) << '-' << endl;

我认为这可能有效:

cout.unsetf(ios::manipulatorname) // Howerver I dont see a manipulator called setfill

我走错了路吗?

推荐答案

看看

Have a look at the Boost.IO_State_Savers, providing RAII-style scope guards for the flags of an iostream.

示例:

#include <boost/io/ios_state.hpp>

{
  boost::io::ios_all_saver guard(cout); // Saves current flags and format

  cout << setw(14) << "  CHARGE/ROOM" << endl;
  cout << setfill('-') << setw(11) << '-' << "  " << setw(15) << '-' << "   " << setw(11) << '-' << endl;
// dtor of guard here restores flags and formats
}

库中还包含更多专门的警戒(仅用于填充，宽度或精度等.有关详细信息，请参阅文档.

More specialized guards (for only fill, or width, or precision, etc... are also in the library. See the docs for details.

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