通过.htaccess和PHP美化API的URL [英] Beautify the URL for API by .htaccess and PHP
问题描述
考虑到我正在请求此URL进行JSON api响应.
Consider that I am requesting this url for a JSON api response.
// url that user will type in the browser address bar
example.com/api/user/0001
我有2个选项:
选项A
重定向将像这样.但是浏览器中的地址将与以前相同.
I have 2 Options:
Option A
The redirection will be like this. But The address in the browser will be the same like before.
example.com?get1=api&get2=user&get3=0001
?get1=xxxxxx
和&get2=xxxxxx
,并且很重要.如果网址中有更多的斜杠(/),则会添加更多的GET请求,例如&get4=xxxxx
&get5=xxxxx
,依此类推.
The
?get1=xxxxxx
and&get2=xxxxxx
and is IMPORTANT. if there is more slashes (/) in the url it will add more GET request like this&get4=xxxxx
&get5=xxxxx
and so on.
然后,我将像这样从$_GET['reques']
方法获取确切的信息!
Then I will get the exact information form the $_GET['reques']
method like this!
$var_request = $_GET['get1'];
$var_type = $_GET['get2'];
$var_id = $_GET['get3'];
选项B
重定向将像这样.但是浏览器中的地址将与以前相同.
Option B
The redirection will be like this. But The address in the browser will be the same like before.
example.com?request=api/user/0001
然后我将这样分解api/user/0001
来获得确切的信息
Then I will get the exact information by exploding the api/user/0001
like this
// Geting request by $_GET
$request = $_GET['request'];
// Exploding by the (/)
$api = explode("/", $request);
// Getting my desired information
$var_request = $api[0];
$var_type = $api[1];
$var_id = $api[2];
记住:URL与以前相同.它看起来不应该像
?get=
这样.该网址在浏览器网址栏中仍应为example.com/api/user/0001
.
Remember: The URL will be same as before. It should not look like
?get=
this. The url should be stillexample.com/api/user/0001
in the browser url bar.
推荐答案
我认为选项B 会更容易实现.可能的解决方案是-
I think Option B will be easier to do this. Possible solution is-
RewriteEngine On
RewriteBase /
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule (.+)$ ?request=$1 [L]
它重定向-example.com/api/user/0001
到example.com?request=api/user/0001
,而无需更改浏览器中网址栏中的地址.
It redirects - example.com/api/user/0001
to example.com?request=api/user/0001
Without changing the address in the url bar in you browser.
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