将[十六进制]字节数组转换为Char数组或字符串类型+ Arduino [英] Convert Byte array [in Hex] to Char array or String type + Arduino

问题描述

我需要将十六进制的字节数组转换为String.

I need to convert byte array which is in hex to String.

例如:

byte array[4] = {0xAB, 0xCD, 0xEF, 0x99};
//array[0] = 0xAB;
//array[1] = 0xCD;
//array[2] = 0xEF;
//array[3] = 0x99;

在上方转换为:

char number[9]; //Should be "ABCDEF99"

反之亦然.那就是将char数组转换为字节数组

I have done it vice versa. That is convert char array to byte array

char CardNumber[9] = "ABCDEF99";
byte j;
auto getNum = [](char c)
{
  return c > '9' ? c - 'a' + 10 : c - '0';
};

char arr[10];
char i;
byte *ptr = out;

for (i = 0; i < 8; i++)
{
  arr[i] = CardNumber[i];
}

for (char *index = arr ; *index ; ++index, ++ptr )
{
  *ptr = (getNum( *index++ ) << 4) + getNum(*index);
}

//Check converted byte values.
Serial.print("Card Number in Bytes :");
for (j = 0; j < 4; j++)
{
  Serial.print(out[j], HEX );
}
Serial.println();

推荐答案

您需要遍历数组，并在字符串缓冲区中添加两个字符(每个半字节).
最后，添加空终止符.

You need to go trough the array and add two characters (for each nibble) to the string buffer.
At the end you add the null terminator.

void array_to_string(byte array[], unsigned int len, char buffer[])
{
    for (unsigned int i = 0; i < len; i++)
    {
        byte nib1 = (array[i] >> 4) & 0x0F;
        byte nib2 = (array[i] >> 0) & 0x0F;
        buffer[i*2+0] = nib1  < 0xA ? '0' + nib1  : 'A' + nib1  - 0xA;
        buffer[i*2+1] = nib2  < 0xA ? '0' + nib2  : 'A' + nib2  - 0xA;
    }
    buffer[len*2] = '\0';
}

然后将其用作:

byte array[4] = {0xAB, 0xCD, 0xEF, 0x99};
char str[32] = "";
array_to_string(array, 4, str);
Serial.println(str);

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