将字节数组 [十六进制] 转换为字符数组或字符串类型 + Arduino [英] Convert Byte array [in Hex] to Char array or String type + Arduino

问题描述

我需要将十六进制的字节数组转换为字符串.

I need to convert byte array which is in hex to String.

例如:

byte array[4] = {0xAB, 0xCD, 0xEF, 0x99};
//array[0] = 0xAB;
//array[1] = 0xCD;
//array[2] = 0xEF;
//array[3] = 0x99;

转换为:

char number[9]; //Should be "ABCDEF99"

反之亦然.也就是将字符数组转换为字节数组

I have done it vice versa. That is convert char array to byte array

char CardNumber[9] = "ABCDEF99";
byte j;
auto getNum = [](char c)
{
  return c > '9' ? c - 'a' + 10 : c - '0';
};

char arr[10];
char i;
byte *ptr = out;

for (i = 0; i < 8; i++)
{
  arr[i] = CardNumber[i];
}

for (char *index = arr ; *index ; ++index, ++ptr )
{
  *ptr = (getNum( *index++ ) << 4) + getNum(*index);
}

//Check converted byte values.
Serial.print("Card Number in Bytes :");
for (j = 0; j < 4; j++)
{
  Serial.print(out[j], HEX );
}
Serial.println();

推荐答案

您需要遍历数组并向字符串缓冲区添加两个字符(每个半字节).
最后添加空终止符.

You need to go trough the array and add two characters (for each nibble) to the string buffer.
At the end you add the null terminator.

void array_to_string(byte array[], unsigned int len, char buffer[])
{
    for (unsigned int i = 0; i < len; i++)
    {
        byte nib1 = (array[i] >> 4) & 0x0F;
        byte nib2 = (array[i] >> 0) & 0x0F;
        buffer[i*2+0] = nib1  < 0xA ? '0' + nib1  : 'A' + nib1  - 0xA;
        buffer[i*2+1] = nib2  < 0xA ? '0' + nib2  : 'A' + nib2  - 0xA;
    }
    buffer[len*2] = '\0';
}

然后您将其用作:

byte array[4] = {0xAB, 0xCD, 0xEF, 0x99};
char str[32] = "";
array_to_string(array, 4, str);
Serial.println(str);

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