将十六进制值附加到字符串 [英] Appending hex value to string

问题描述

$temp = 'abc'.0x12;
print $temp; # prints abc18

在将十六进制值附加到字符串时，它将转换为十进制值，最终结果是字符串.我想要的是将十六进制的ascii值附加到字符串中.

While appending the hex value to string it is getting converted to decimal value and final result is string. what I want is that the ascii value of the hex should get appended to the string.

例如ASCII中的0x12是DC2(设备控制2).

for e.g. 0x12 in ascii is DC2 (device control 2).

推荐答案

我认为Sly Raskal处在正确的轨道上，但使用%c代替了%x，所以:

I think Sly Raskal was on the right track but instead of %x use %c, so:

my $hex = 0x12;
my $ascii = sprintf "%c", $hex;
my $temp = 'abc' . $ascii;

我认为这可以为您提供所需的结果.我是从 http://www.perlmonks.org/?node_id=191039 获得的.

I think this gives the result you were looking for. I got it from http://www.perlmonks.org/?node_id=191039 .

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