如何断言groupType！= null包含4个分支 [英] How does assert groupType != null contain 4 branches

问题描述

我需要测试以下代码.

public List<PatientGroup> findGroups(final String groupType) throws HwBaseAppException
{
    assert groupType != null;//4 branches here
    CriteriaBuilder criteriaBuilder=persistence.getCriteriaBuilder();
    CriteriaQuery<PatientGroup> query = criteriaBuilder.createQuery(PatientGroup.class);
    Root<PatientGroup> patientGroupRoot = query.from(PatientGroup.class);
    Predicate condition=criteriaBuilder.equal(patientGroupRoot.get(PatientGroup_.active), Boolean.TRUE);
    Join<PatientGroup, GroupSubType> groupSubTypeRoot = patientGroupRoot.join(PatientGroup_.groupSubType);
    Predicate condition1=criteriaBuilder.equal(groupSubTypeRoot.get(GroupSubType_.groupTypeCode), groupType);
    query.where(condition,condition1);
    query.orderBy(criteriaBuilder.asc(patientGroupRoot.get(PatientGroup_.name)));
    TypedQuery<PatientGroup> tq = persistence.createQuery(query);       
    List<PatientGroup> collections = tq.getResultList();
    return initializeGroupRelationships(collections);
}

在我的测试案例中，我同时传递了应覆盖两个分支的null和非null值，但是代码覆盖率表明缺少4个分支中的1个，另外2个分支又是什么? 以下是我的测试用例.

In my test case i am passing both null and not null values which should cover both the branches however Code coverage says 1 of 4 branches missed.What are the other 2 branches? Below are my test cases.

 @Test
    public void testFindGroups_1()
        throws HwBaseAppException
    {   
        Mockito.when(persistence.getCriteriaBuilder()).thenReturn(criteriaBuilder);
        Mockito.when(criteriaBuilder.createQuery(PatientGroup.class)).thenReturn(criteriaQuery);
        Mockito.when(criteriaQuery.from(PatientGroup.class)).thenReturn(patientGroupRoot);
        Mockito.when(patientGroupRoot.join(PatientGroup_.groupSubType)).thenReturn(groupSubTypeRoot);
        Mockito.when(persistence.createQuery(Mockito.any(CriteriaQuery.class))).thenReturn(tq);
        Mockito.when(tq.getResultList()).thenReturn(arrayList);
        Mockito.when(arrayList.iterator()).thenReturn(iterator);
        Mockito.when(iterator.hasNext()).thenReturn(true).thenReturn(false);
        Mockito.when(iterator.next()).thenReturn(patientGroup);
        groupServiceDAOImpl.findGroups("groupType");    
    }
    @Test(expected=AssertionError.class)
    public void testFindGroups_2()
        throws HwBaseAppException
    {   
        groupServiceDAOImpl.findGroups(null);   
    }

推荐答案

EclEmma Eclipse插件使用 JaCoCo提供覆盖率分析库，然后依次分析字节码.让我们举一个简化的例子:

EclEmma Eclipse plugin provides coverage analysis using JaCoCo library, which in his turn analyzes bytecode. Let's take a simplified example:

class Example {
  void example(Object x) {
    assert x != null;
  }
}

让我们看一下它的字节码:

And let's have a look on its bytecode:

javac Example.java
javap -v Example

外观如下:

 0: getstatic     #2                  // Field $assertionsDisabled:Z
 3: ifne          18
 6: aload_1
 7: ifnonnull     18
10: new           #3                  // class java/lang/AssertionError
13: dup
14: invokespecial #4                  // Method java/lang/AssertionError."<init>":()V
17: athrow
18: return

如您所见-实际上有两个条件:

As you can see - there are actually 2 conditions:

1. 已启用断言(ifne)
2. x不是null(ifnonnull)

1. assertions enabled (ifne)
2. x is not null (ifnonnull)

还有4种可能的变体.

这篇关于如何断言groupType！= null包含4个分支的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！