我怎么能简化表单验证? [英] How can I simplify form validation?

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问题描述

下code似乎工作pretty好做基本要求表单验证。

The code below seems to work pretty well for doing basic required form validation.

该表单显示一个红色的姓名为必填项的时候现场脏+无效,消息的大!的如果字段是消息脏+有效。

The form displays a red Name is required message when the field is dirty + invalid and a Great! message if the field is dirty + valid.

但它是有重复的形式是code的每一个领域一个烂摊子:

But it's a mess having repeat this code for each and every field in the form:

<form name="myForm">
    <div class="control-group" 
     ng-class="{error: myForm.name.$invalid && myForm.name.$dirty}">
        <label>Name:</label>
        <input type="text" name="name" ng-model="user.name" required/>
        <span ng-show="myForm.name.$invalid && myForm.name.$dirty" 
            class="help-inline">Name is required</span>
        <span ng-show="myForm.names.$valid && myForm.names.$dirty">Great!</span>
    </div>
</form>

我希望能够指定 NG-节目纳克级属性在一些更简单的方法

I would like to be able to specify the ng-show and ng-class attributes in some easier way.

推荐答案

您可以做到这一点的方法之一是抽象您的验证前pression到范围的方法:

One way you could do it is to abstract your validation expression to scope methods:

<大骨节病> PLUNKER

<div class="control-group" ng-class="{error: isInvalid('name')}">
  <label>Name:</label>
  <input type="text" name="name" placeholder="Name" ng-model="user.name" required/>
  <span ng-show="isInvalid('name')" class="help-inline">Name is required</span>
  <span ng-show="isValid('name')">Great!</span>
</div>

控制器

function Ctrl($scope) {
  $scope.isInvalid = function(field){
    return $scope.myForm[field].$invalid && $scope.myForm[field].$dirty;
  };

  $scope.isValid = function(field){
    return $scope.myForm[field].$valid && $scope.myForm[field].$dirty;
  };

}

这篇关于我怎么能简化表单验证?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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