bash命令在特定行号范围内打印列 [英] bash command to print column at specific range of line numbers

问题描述

我试图在第5到5 + Y行中获取X列中的值.我猜想有一种使用awk进行此操作的快速方法.怎么做?

I'm trying to get the values in column X at lines 5 to 5 + Y. I'm guessing there's a quick way to do this with awk. How is this done?

推荐答案

我认为这对您有效，未经测试:

I think this will work for you, untested:

awk 'NR >= 5 && NR <= 5 + Y { print $X }' file.txt

很明显，用X和Y代替一些实际值.

Obviously, substitute X and Y for some real values.

如果X和Y是shell变量:

If X and Y are shell variables:

awk -v column="$X" -v range="$Y" 'NR >= 5 && NR <= 5 + range { print $column }' file.txt

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