将awk发现的每个事件存储到数组中 [英] Store each occurence found by awk to an array

问题描述

我之前的问题被标记为重复"，我被指向 this 和

My previous question was flagged "duplicate" and I was pointed to this and this. The solutions provided on those threads does not solve this at all.

file.txt的内容:

Content of file.txt:

Some line of text 0
Some line of text 1
Some line of text 2
PATTERN1
Some line of text 3
Some line of text 4
Some line of text 5
PATTERN2
Some line of text 6
Some line of text 7
Some line of text 8
PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2
Some line of text 12
Some line of text 13
Some line of text 14

我需要提取"PATTERN1"和"PATTERN2"在它们之间加上+行，并且以下命令可以完美地完成此操作:

I need to extract "PATTERN1" and "PATTERN2" + lines in between, and the following command does this perfectly:

awk'/PATTERN1//，/PATTERN2/'./file.txt

awk '/PATTERN1 /,/PATTERN2/' ./file.txt

输出:

PATTERN1
Some line of text 3
Some line of text 4
Some line of text 5
PATTERN2

PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2

但是现在我正在尝试创建一个bash脚本，该脚本:

But now I am trying to create a bash script that:

1. 使用awk查找PATTERN1和PATTERN2之间的线
2. 存储每次出现的PATTERN1 +之间的行+ PATTERN2 数组
3. 执行1& 2，直到文件结尾.

1. uses awk to find the lines between PATTERN1 and PATTERN2
2. store each occurrence of PATTERN1 + lines in between + PATTERN2 in an array
3. does 1 & 2 until the end of file.

要澄清.意思是在引号内存储以下行:

To clarify. Means store the following lines inside the quotes:

"PATTERN1
Some line of text 3
Some line of text 4
Some line of text 5
PATTERN2"

到array[0]

并在引号内存储以下行:

and store the following lines inside the quotes:

"PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2"

到array[1]

以此类推.....如果出现PATTERN1和PATTERN2的次数更多

and so on..... if there are more occurrence of PATTERN1 and PATTERN2

我目前拥有的东西:

#!/bin/bash
var0=`cat ./file.txt`
mapfile -t thearray < <(echo "$var0" | awk '/PATTERN1 /,/PATTERN2/')

以上操作无效.
而且，我尽可能不使用mapfile，因为该脚本可能在不支持该文件的系统上执行.

The above does not work.
And as much as possible I do not want to use mapfile, because the script might be executed on a system that does not support it.

基于提供的此链接:

myvar=$(cat ./file.txt)
myarray=($(echo "$var0" | awk '/PATTERN1 /,/PATTERN2/')) 

但是当我做echo ${myarray[1]}

我得到一个空白的答复.

I get a blank response.

当我做echo ${myarray[0]}

我得到:

PATTERN1
Some line of text 3
Some line of text 4
Some line of text 5
PATTERN2

PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2

回显${myarray[0]}

PATTERN1
Some line of text 3
Some line of text 4
Some line of text 5
PATTERN2

我echo ${myarray[1]}

PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2

任何帮助都会很棒.

推荐答案

根据 Charles 的建议...

while IFS= read -r -d '' x; do array+=("$x"); done < <(awk '
  /PATTERN1/,/PATTERN2/ { if ( $0 ~ "PATTERN2" ) { x=$0; printf "%s%c",x,0; next }
                          print }' ./file.txt)

我重新格式化了.有点忙，难以阅读.

I reformatted it. It was getting kinda busy and hard to read.

并对其进行测试-

$: echo "[${array[1]}]"
[PATTERN1
Some line of text 9
Some line of text 10
Some line of text 11
PATTERN2]

顺便说一句，在数据元素中包含冗余的哨兵值对我来说似乎很奇怪，所以如果要剥离这些值:

As an aside, it seems very odd to me to include the redundant sentinel values in the data elements, so if you want to strip those:

$: while IFS= read -r -d '' x; do array+=("$x"); done < <(
    awk '/PATTERN1/,/PATTERN2/{ if ( $0 ~ "PATTERN1" ) { next }
      if ( $0 ~ "PATTERN2" ) { len--; 
        for (l in ary) { printf "%s%c", ary[l], l<len ? "\n" : 0; } 
        delete ary; len=0; next }
      ary[len++]=$0;
    }' ./file.txt )

$: echo "[${array[1]}]"
[Some line of text 9
Some line of text 10
Some line of text 11]

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