基于文件位置而不是当前工作目录的相对路径 [英] Relative paths based on file location instead of current working directory

问题描述

给出:

some.txt
dir
 |-cat.sh

cat.sh具有以下内容:

With cat.sh having the content:

cat ../some.txt

然后在dir内运行./cat.sh可以正常工作，而在与dir相同级别上运行./dir/cat.sh则可以.我希望这归因于不同的工作目录.有没有一种简单的方法可以使路径../some.txt相对于cat.sh的位置?

Then running ./cat.sh inside dir works fine while running ./dir/cat.sh on the same level as dir does not. I expect this to be due to the different working directories. Is there an easy way to make the path ../some.txt relative to the location of cat.sh?

推荐答案

您要做的是获取脚本的绝对路径(可通过${BASH_SOURCE[0]}获得)，然后使用它来获取父目录和cd脚本开头的内容.

What you want to do is get the absolute path of the script (available via ${BASH_SOURCE[0]}) and then use this to get the parent directory and cd to it at the beginning of the script.

#!/bin/bash
parent_path=$( cd "$(dirname "${BASH_SOURCE[0]}")" ; pwd -P )

cd "$parent_path"
cat ../some.text

这将使您的shell脚本独立于您从何处调用它而工作.每次运行它时，就像在dir中运行./cat.sh一样.

This will make your shell script work independent of where you invoke it from. Each time you run it, it will be as if you were running ./cat.sh inside dir.

请注意，此脚本仅在您直接调用脚本(即不通过符号链接)时才有效，否则，找到脚本的当前位置会更加棘手)

Note that this script only works if you're invoking the script directly (i.e. not via a symlink), otherwise the finding the current location of the script gets a little more tricky)

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