Bash中的正则表达式:不想包含目录 [英] Regex in Bash: not wanting to include directories

问题描述

我有一张使用以下行收集的图像列表:

I have a list of images, collected using the following line:

# find . -mindepth 1 -type f -name "*.JPG" | grep "MG_[0-9][0-9][0-9][0-9].JPG"

输出:

./DCIM/103canon/IMG_0039.JPG
./DCIM/103canon/IMG_0097.JPG
./DCIM/103canon/IMG_1600.JPG
./DCIM/103canon/IMG_2317.JPG
./DCIM/IMG_0042.JPG
./DCIM/IMG_1152.JPG
./DCIM/IMG_1810.JPG
./DCIM/IMG_2564.JPG
./images/IMG_0058.JPG
./images/IMG_0079.JPG
./images/IMG_1233.JPG
./images/IMG_1959.JPG
./images/IMG_2012/favs/IMG_0039.JPG
./images/IMG_2012/favs/IMG_1060.JPG
./images/IMG_2012/favs/IMG_1729.JPG
./images/IMG_2012/favs/IMG_2013.JPG
./images/IMG_2012/favs/IMG_2317.JPG
./images/IMG_2012/IMG_0079.JPG
./images/IMG_2012/IMG_1403.JPG
./images/IMG_2012/IMG_2102.JPG
./images/IMG_2013/IMG_0060.JPG
./images/IMG_2013/IMG_1311.JPG
./images/IMG_2013/IMG_1729.JPG
./images/IMG_2013/IMG_2013.JPG
./IMG_0085.JPG
./IMG_1597.JPG
./IMG_2288.JPG

但是我只想要最后一部分，IMG_ \ d \ d \ d \ d.JPG.我已经尝试了数百种正则表达式，这是给我最好结果的一种.有没有办法只打印文件名而不先显示目录树，还是仅取决于正则表达式?

however I only want the very last portion, the IMG_\d\d\d\d.JPG. I have tried hundreds of regular expressions and this is the one that gives me the best result. Is there a way to only print out the filename without the directory tree before it or is is solely down to the regex?

谢谢

推荐答案

应该是

find . -mindepth 1 -type f -name "*MG_[0-9][0-9][0-9][0-9].JPG" -printf "%f\n"

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