Bash:当前目录中匹配正则表达式的文件总大小 [英] Bash: total size of file in current directory matching regular expression

问题描述

ls | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }' 

这段代码使用[0-9]"作为reg expr返回0，在当前文件夹中有2个文件名为:1"和6"，每个文件的大小为138字节.

This code is returning 0 using "[0-9]" as reg expr, in current folder there are 2 files named: "1" and "6", each one with size of 138bytes.

谁能帮我找出问题所在?

Anyone could help me to find the problem?

推荐答案

您只是缺少 ls 的 -l 选项.

You're just missing the -l option to ls.

ls -l | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }' 

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