为异步发送缓冲区保留内存(增强的asio套接字) [英] Reserving memory for asynchronous send buffers (boost asio sockets)

问题描述

我正在尝试将即弃型UDP发送功能的实现方式从同步更改为异步.

I'm trying to change the implementation of a fire-and-forget UDP send-function from being synchronous to asynchronous.

当前的简化同步功能如下:

The current simplified synchronous function looks like this:

ssize_t UDPTransport::send_to(const char * buffer, size_t bufferSize) {
    return mPSocket->send_to(boost::asio::buffer(buffer, bufferSize), mOutputEndpoint);
}

我已经设置了thread_group并将io_service::run()设置为可以使用它.但是，问题是我无法保证在此调用完成之后buffer将存在.我需要存储缓冲区的内容，然后知道什么时候空闲，以便以后可以重用或删除它.以下内容很简单，但是如果我触发了两个send_to调用，那么我无法保证handle_send会以相同的顺序被调用，并且我可能会pop仍然需要一些东西！

I've got a thread_group set up and io_service::run() is set to use it. However, the problem is that I have no guarantee that buffer will exist after this call has completed. I need to store the contents of the buffer and then know when it is free so that I can re-use it later or delete it. The following is simple, but if I fire off two send_to calls, then I have no guarantee that the handle_send will be called in the same order and I might pop something that is still needed!

ssize_t UDPTransport::send_to(const char * buffer, size_t bufferSize) {

    boost::asio::mutable_buffer b1 = boost::asio::buffer(buffer,bufferSize);
    mMutex.lock();
    mQueue.push(b1);

    mPSocket->async_send_to(mQueue.back(), mOutputEndpoint,
                            boost::bind(&UDPTransport::handle_send, this,
                                        boost::asio::placeholders::error,
                                        boost::asio::placeholders::bytes_transferred));

    mMutex.unlock();
    return bufferSize;
}

void UDPTransport::handle_send(const boost::system::error_code& error,
                               std::size_t bytes_transferred)
{
    mMutex.lock();
    mQueue.pop();
    mMutex.unlock();
}

什么是存储异步缓冲区，然后在不再需要它时清理它的好方法?

What's a good way to store an asynchronous buffer, then clean it up once it's no longer needed?

在线阅读下面可能是一种更简单的方法，但是我不知道我是否相信它.为什么共享指针会决定在调用处理程序之后才取消自身分配?

Reading online an even simpler way may be below, but I don't know if I trust it. Why would a shared pointer decide to not de-allocate itself until after the handler has been called?

ssize_t UDPTransport::send_to(const char * buffer, size_t bufferSize) 
{
    auto buf = std::make_shared<std::string>(buffer, bufferSize);
    mPSocket->async_send_to(boost::asio::buffer(*buf), mOutputEndpoint,
                            boost::bind(&UDPTransport::handle_send, this,
                                        boost::asio::placeholders::error,
                                        boost::asio::placeholders::bytes_transferred));
    return bufferSize;
}

推荐答案

我通常要做的是将其包装在继承自std :: enable_shared_from_this<>的类中，如下所示:

What I usually do is to wrap it in a class that inherits from std::enable_shared_from_this<> something along the following lines:

class Sender : public std::enable_shared_from_this<Sender> {
 public:
  using CompletionHandler =
      std::function<void(const boost::system::error_code& ec,
                         size_t bytes_transferred,
                         std::shared_ptr<Sender> sender)>;

  ~Sender() = default;

  template<typename... Args>
  static std::shared_ptr<Sender> Create(Args&&... args) {
    return std::shared_ptr<Sender>(new Sender(std::forward<Args>(args)...));
  }

  void AsyncSendTo(const char* buffer, size_t buffer_size,
                   CompletionHandler completion_handler) {
    data_.append(buffer, buffer_size);
    socket.async_send_to(
        boost::asio::buffer(data_), endpoint_,
        [self = shared_from_this(),
         completion_handler = std::move(completion_handler)]
        (const boost::system::error_code& ec,
         size_t bytes_transferred) mutable {
          completion_handler(ec, bytes_transferred, std::move(self));
        });
  }

 private:
  Sender() = default;
  Sender(const Sender&) = delete;
  Sender(Sender&&) = delete;
  Sender& operator=(const Sender&) = delete;
  Sender& operator=(Sender&&) = delete;

  SocketType socket_;
  EndpointType endpoint_;
  std::string data_;
}

显然，您必须保证completion_handler的寿命.但是除此之外，完成处理程序将在完成后返回一个有效的std::shared_ptr<Sender>，并且您可以使用发件人携带的数据进行所需的任何操作.

Obviously, you have to guarantee the completion_handler's lifetime. But other than that, the completion handler is gonna come back with a valid std::shared_ptr<Sender> whenever it's done and you can do whatever you need with the data Sender carries.

在您发布的示例中，buf将离开范围并在send_to返回时被销毁，除非您首先在bind中捕获了它.

In the example you posted, buf would leave scope and get destroyed on send_to return, unless you first captured it in bind.

脚注1:可能需要删除那些std::move()，这取决于您的编译器在lambda上是否兼容C ++ 14.

Footnote1: Those std::move()s might need to be removed depending on whether your compiler is C++14 compatible when it comes to lambdas.

Footnote2:除非绝对需要利用它的动态特性，否则请远离bind.

Footnote2: Stay away from bind unless you absolutely need to exploit its dynamic nature.

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