char数组初始化程序中的多余元素错误 [英] Excess elements in char array initializer error
本文介绍了char数组初始化程序中的多余元素错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我一直在尝试执行以下代码。.但是,我一遍又一遍地得到相同的错误,我不知道为什么!
I've been trying to execute the following code.. However, I keep getting the same errors over and over again and I don't know why!
我的代码:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>
int main(void){
int randomNum;
char takenWords[4];
char words[20]={"DOG", "CAT", "ELEPHANT", "CROCODILE", "HIPPOPOTAMUS", "TORTOISE", "TIGER", "FISH", "SEAGULL", "SEAL", "MONKEY", "KANGAROO", "ZEBRA", "GIRAFFE", "RABBIT", "HORSE", "PENGUIN", "BEAR", "SQUIRREL", "HAMSTER"};
srand(time(NULL));
for(int i=0; i<4; i++){
do{
randomNum = (rand()%20);
takenWords[i]=words[randomNum];
}while((strcmp(&words[randomNum], takenWords) == 0)&&((strcmp(&words[randomNum], &takenWords[i])==0)));
printf("%s\n", &words[randomNum]);
}
getchar();
return 0;
}
我已经计算了我在数组中输入的元素数量,不超过20!
I have counted the number of elements which I entered in the array and they do not exceed 20!
为什么我仍然不断收到隐式转换丢失整数精度错误的信息?
Also, why do I keep getting the 'Implicit conversion loses integer precision error'?
推荐答案
我想您想创建一个指针数组而不是字符数组。
I guess you want to make arrays of pointers instead of arrays of characters.
尝试以下操作:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>
int main(void){
int randomNum;
const char *takenWords[4];
const char *words[20]={"DOG", "CAT", "ELEPHANT", "CROCODILE", "HIPPOPOTAMUS", "TORTOISE", "TIGER", "FISH", "SEAGULL", "SEAL", "MONKEY", "KANGAROO", "ZEBRA", "GIRAFFE", "RABBIT", "HORSE", "PENGUIN", "BEAR", "SQUIRREL", "HAMSTER"};
srand(time(NULL));
for(int i=0; i<4; i++){
int dupe=0;
do{
randomNum = (rand()%20);
takenWords[i]=words[randomNum];
dupe=0;
for(int j=0;j<i;j++){
if(strcmp(words[randomNum],takenWords[j])==0)dupe=1;
}
}while(dupe);
printf("%s\n", words[randomNum]);
}
getchar();
return 0;
}
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