bash“ read -a”在空分隔的字符串变量上循环 [英] bash “read -a” looping on null delimited string variable

问题描述

我一直在阅读这篇文章： bash 用于循环使用空定界的字符串变量
，看看我是否能够处理数组中包含空格的任意文本。

I've been reading up on this post: bash "for in" looping on null delimited string variable to see if I would be able to handle arbitrary text containing spaces inside an array.

根据文章上面的工作正常：

Based on the post above this works fine:

while IFS= read -r -d '' myvar; do echo $myvar; done < <(find . -type f -print0)

为了检查我的理解，我也这样做了（仍然可以正常工作）：

To check my understanding I also did this (which still works fine):

while IFS= read -r -d '' myvar; do echo $myvar; done < <(printf "%s\0" 'a b' 'c d')

但是，然后尝试将输出存储在数组中会出错：

However, then I attempt storing the output in an array it goes wrong:

IFS= read -r -d '' -a myvar < <(printf "%s\0" 'a b' 'c d')

数组仅保存 ab ，而不保存 cd ：

The array holds only a b and not c d:

echo ${myvar[@]}
a b

显然，这里有一个更好的细节。谢谢您的帮助。

Apparently, there is a finer detail I am missing here. Thanks for any help.

PS。我正在运行：

GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin14)
Copyright (C) 2007 Free Software Foundation, Inc.

推荐答案

在 bash 4.4中， readarray 命令获得了 -d 选项类似于 read 的相同选项。

In bash 4.4, the readarray command gained a -d option analogous to the same option for read.

$ IFS= readarray -d '' myvar < <(printf "%s\0" 'a b' 'c d')
$ printf "%s\n" "${myvar[@]}"
a b
c d

如果必须支持早期版本，则需要显式循环输出。

If you must support earlier versions, you need to loop over the output explicitly.

while IFS= read -d '' line; do
    myvar+=( "$line" )
done < <(printf "%s\0" 'a b' 'c d')

这篇关于bash“ read -a”在空分隔的字符串变量上循环的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！