庆典＆QUOT;在＆QUOT;在循环空分​​隔字符串变量 [英] bash "for in" looping on null delimited string variable

问题描述

我想通过的文件列表进行迭代，而无需关心文件名可能包含哪些字符，所以我用空字符分隔列表。在code将更好地解释的东西。

I want to iterate through a list of files without caring about what characters the filenames might contain, so I use a list delimited by null characters. The code will explain things better.

# Set IFS to the null character to hopefully change the for..in
# delimiter from the space character (sadly does not appear to work).
IFS=$'\0'

# Get null delimited list of files
filelist="`find /some/path -type f -print0`"

# Iterate through list of files
for file in $filelist ; do
    # Arbitrary operations on $file here
done

以下code从文件中读取数据时的作品，但我需要从包含文本变量来阅读。

The following code works when reading from a file, but I need to read from a variable containing text.

while read -d $'\0' line ; do
    # Code here
done < /path/to/inputfile

谢谢！

推荐答案

在bash，那么你可以使用下面的字符串

In bash you can use a here-string

while IFS= read -r -d '' line ; do
    # Code here
done <<<"$var"

请注意，您应内嵌 IFS = ，只使用 -d''但要确保有一个在D和第一个单引号之间的空间。此外，添加了 -r 标志忽略逃逸。

Note that you should inline the IFS= and just use -d '' but make sure there is a space between the 'd' and the first single-quote. Also, add the -r flag to ignore escapes.

此外，这是不是你的问题的一部分，但我可能会建议一个更好的办法时使用找到做你的脚本;它使用进程替换。

Also, this isn't part of your question but might I suggest a better way to do your script when using find; it uses process substitution.

while IFS= read -r -d '' file; do
    # Arbitrary operations on "$file" here
done < <(find /some/path -type f -print0)

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