如何在processStartInfo中传递多个参数? [英] How to pass multiple arguments in processStartInfo?
问题描述
我想从 c#
代码运行一些 cmd
命令。我关注了一些博客和教程并获得了答案,但是我有点困惑,即我应该如何传递多个参数?
I want to run some cmd
command from c#
code. I followed some blogs and tutorial and got the answer, but I am in little bit confused i.e how should I pass multiple arguments?
我使用以下代码:
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
startInfo.FileName = "cmd.exe";
startInfo.Arguments =
...
什么是<$以下命令行代码的c $ c> startInfo.Arguments 值是
-
makecert -sk服务器-sky exchange -pe -n CN = localhost -ir LocalMachine -is Root -ic MyCA.cer -sr LocalMachine -ss My MyAdHocTestCert.cer
netsh http add sslcert ipport = 127.0.0.1:8085 certhash = 0000000000003ed9cd0c315bbb6dc1c08da5e6 appid = {00112233-4455-6677-8899-AABBCCDDEEFF} clientcertnegotiation = enable
推荐答案
它纯粹是一个字符串:
startInfo.Arguments = "-sk server -sky exchange -pe -n CN=localhost -ir LocalMachine -is Root -ic MyCA.cer -sr LocalMachine -ss My MyAdHocTestCert.cer"
当然,当参数包含空格时,必须使用\ \对其进行转义,例如:
Of course, when arguments contain whitespaces you'll have to escape them using \" \", like:
"... -ss \"My MyAdHocTestCert.cer\""
请参见 MSDN 。
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